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Author Topic: All Mechanics DOUBTS HERE!!!  (Read 96395 times)

Offline your sister

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Re: All Mechanics DOUBTS HERE!!!
« Reply #480 on: May 16, 2011, 06:31:37 am »
goodluck for M1 cie-ers :)
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Offline HUSH1994

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Re: All Mechanics DOUBTS HERE!!!
« Reply #481 on: May 16, 2011, 07:05:19 am »
Quote from: your sister on May 16, 2011, 06:31:37 am
goodluck for M1 cie-ers :)

Thanks and same to you,exam in 2 hours :D
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........

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Re: All Mechanics DOUBTS HERE!!!
« Reply #482 on: May 16, 2011, 03:23:20 pm »
Quote from: SkyPilotage on May 14, 2011, 09:11:32 pm
Hey guys what rule do you use for work??
I use Work by Driving force=change in p.e+change in k.e+work agnst resistance
Others use Work by D - Work agnst R = Final M.E - Initial M.E???
I know both are the same but which is prefered to be used as A RULE before substituting..???

Another question..
When they ask for Loss in K.e..Do we give it as +ve loss or -ve(change) Do you get what I mean?? For ex: if they ask for change answer wod be -ve what if they ask for Loss we give as +ve right?? What abt the equation (rule( do we give it as 0.5m(u^2-v^2) or 0.5(v^2-u^2) then state its -ve because its loss??)
Plz answer me If you are sure  ;)
Thank You ..

Do you by any chance study from Mr Shariq in Jeddah
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Offline SkyPilotage

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Re: All Mechanics DOUBTS HERE!!!
« Reply #483 on: May 18, 2011, 02:32:43 pm »
Quote from: Dumb economist on May 16, 2011, 03:23:20 pm
Do you by any chance study from Mr Shariq in Jeddah
Mr. Shariq? Nope...
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Offline mdwael

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Re: All Mechanics DOUBTS HERE!!!
« Reply #484 on: May 18, 2011, 06:41:06 pm »
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Offline SkyPilotage

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Re: All Mechanics DOUBTS HERE!!!
« Reply #485 on: May 18, 2011, 06:43:27 pm »
Quote from: mdwael on May 18, 2011, 06:41:06 pm
Do you still want the answer?
lol i doubt :D
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Offline The Golden Girl =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #486 on: May 18, 2011, 07:26:12 pm »
Quote from: mdwael on May 18, 2011, 06:41:06 pm
Do you still want the answer?

Thx but I've already done the exam :)
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Offline username

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Re: All Mechanics DOUBTS HERE!!!
« Reply #487 on: May 19, 2011, 07:13:15 am »
so we can discuss yet???
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elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #488 on: May 19, 2011, 07:22:43 am »
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Offline aloha32

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Re: All Mechanics DOUBTS HERE!!!
« Reply #489 on: May 24, 2011, 09:38:01 pm »
Hi
Can anyone please explain why in June 2005 Qs 7 paper we take moments about F and not A?
and Nov 09 Q5 part one for circular motion..how is sin theta = 3/8

and sorry this one's REALLY confusing too..why isn't the speed 10m/s in Q5 Nov 2003 after rebounding at right angles? The mark scheme says "NOT 10m/s" and if you had correct method in 10m/s, there would be no marks eithers. So how did we get 10m/s?

Thank you!
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Offline yasser37

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Re: All Mechanics DOUBTS HERE!!!
« Reply #490 on: May 24, 2011, 10:38:02 pm »
Hi

These are the doubts I have so far
please help  :)

November 09 , 51, Q4 (ii)
November 10 . 53 , Q4(ii)
November 09 , 52 ,Q1
June 10 , 53, Q(i) ---- A Drawing of angles taken would be greatly appreciated
June 09, 5, Q2 (i) Same as above and Q(6) (ii)

I hope that someone can help me before my exam
+rep for helper  :-*
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Offline yasser37

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Re: All Mechanics DOUBTS HERE!!!
« Reply #491 on: May 25, 2011, 07:51:52 am »
anyone?  :(
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Offline yasser37

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Re: All Mechanics DOUBTS HERE!!!
« Reply #492 on: May 25, 2011, 01:55:22 pm »
bump
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elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #493 on: May 25, 2011, 01:56:38 pm »
Quote from: yasser37 on May 24, 2011, 10:38:02 pm
Hi

These are the doubts I have so far
please help  :)

November 09 , 51, Q4 (ii)
November 10 . 53 , Q4(ii)
November 09 , 52 ,Q1
June 10 , 53, Q(i) ---- A Drawing of angles taken would be greatly appreciated
June 09, 5, Q2 (i) Same as above and Q(6) (ii)

I hope that someone can help me before my exam
+rep for helper  :-*


I'll see what I can do.
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elemis

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Re: All Mechanics DOUBTS HERE!!!
« Reply #494 on: May 25, 2011, 02:07:25 pm »
Winter 2009

Question 4

Let us say that at 0.3 seconds the object is travelling at an angle alpha to the horizontal, where tan alpha = 7/24 (as the question states).

We know the horizontal component of the velocity is 24 m/s.

If tan alpha = 7/24 ..... sin alpha = 7/25

Hence, at 0.3s the projectile has a vertical component of velocity of :

25 sin alpha i.e. 7m/s

Using v = u+at you should be able to find the initial VERTICAL component of velocity to be 10m/s.

Can you proceed by yourself now ?

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