Author Topic: All Mechanics DOUBTS HERE!!!  (Read 96362 times)

Offline The Golden Girl =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #465 on: May 14, 2011, 05:13:05 pm »
Hello :)
Could someone help out in the following questions ?
M1 Jan O8 
4 C
6 b c d
7 all of it
I know they are many but please if anyone could explain how we solve them ?
Thanks in advance :D

check this website =>   http://www.examsolutions.co.uk/

the section that has the Edexcel papers :)
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Offline leebux101

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Re: All Mechanics DOUBTS HERE!!!
« Reply #466 on: May 14, 2011, 05:23:41 pm »
ON 2009 P41 q4 , all of it, and can u please explain with a diagram of resolved forces please? =d
can someone please explain this??  :(

Offline iluvme

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Re: All Mechanics DOUBTS HERE!!!
« Reply #467 on: May 14, 2011, 06:01:38 pm »
can someone please explain this??  :(

Here you go, and the iii) sorry its not that legible.
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Offline leebux101

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Re: All Mechanics DOUBTS HERE!!!
« Reply #468 on: May 14, 2011, 07:40:38 pm »
Here you go, and the iii) sorry its not that legible.
u are awesome .

Offline iluvme

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Re: All Mechanics DOUBTS HERE!!!
« Reply #469 on: May 14, 2011, 08:49:19 pm »
Did you get part iii)?
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Offline leebux101

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Re: All Mechanics DOUBTS HERE!!!
« Reply #470 on: May 14, 2011, 08:50:43 pm »
Did you get part iii)?
yup! thanks ALOT!

Offline SkyPilotage

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Re: All Mechanics DOUBTS HERE!!!
« Reply #471 on: May 14, 2011, 09:11:32 pm »
Hey guys what rule do you use for work??
I use Work by Driving force=change in p.e+change in k.e+work agnst resistance
Others use Work by D - Work agnst R = Final M.E - Initial M.E???
I know both are the same but which is prefered to be used as A RULE before substituting..???

Another question..
When they ask for Loss in K.e..Do we give it as +ve loss or -ve(change) Do you get what I mean?? For ex: if they ask for change answer wod be -ve what if they ask for Loss we give as +ve right?? What abt the equation (rule( do we give it as 0.5m(u^2-v^2) or 0.5(v^2-u^2) then state its -ve because its loss??)
Plz answer me If you are sure  ;)
Thank You ..

Offline Blizz_rb93

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Re: All Mechanics DOUBTS HERE!!!
« Reply #472 on: May 14, 2011, 09:33:37 pm »
January 2009 Question 3 b)
help please

Offline iluvme

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Re: All Mechanics DOUBTS HERE!!!
« Reply #473 on: May 14, 2011, 10:10:36 pm »
I believe in killing the messenger. Know why? It sends  message.
~Damon Salvatore~

Offline leebux101

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Re: All Mechanics DOUBTS HERE!!!
« Reply #474 on: May 14, 2011, 10:38:23 pm »
Hey guys what rule do you use for work??
I use Work by Driving force=change in p.e+change in k.e+work agnst resistance
Others use Work by D - Work agnst R = Final M.E - Initial M.E???
I know both are the same but which is prefered to be used as A RULE before substituting..???

Another question..
When they ask for Loss in K.e..Do we give it as +ve loss or -ve(change) Do you get what I mean?? For ex: if they ask for change answer wod be -ve what if they ask for Loss we give as +ve right?? What abt the equation (rule( do we give it as 0.5m(u^2-v^2) or 0.5(v^2-u^2) then state its -ve because its loss??)
Plz answer me If you are sure  ;)
Thank You ..
ok for ur first question , i had the same confusion, but i have learned that logic works best in this kind of problem, For example >
work is done by the driving force to overcome loss in ke and work done against resistance, because they are both actually working against letting an object move ryt? cuz ke is lost bcuz there was resistance.. do u get it? so work dont by driving force = Loss in ke + work done by resistive forces... secondly this formula >> work done by DF - Work done by Resistive forces = gain in KE , apply this to the situation, if u dont get the answer then u need to think logically about the changes invloved...
if u dont understand this, then PLEASE do ASK me again and i will give u specific example from pastpapers,
for ur second problem >>
u can change the formula from 1/2m(v^2 - u^2) to 1/2m(u^2 - v^2) .. we always write the value as postive no matter if its gain or loss
the first formula is for gain because final speed will be greater than initial speed so u subtract v^2 from u^2.
the second formula is for loss cuz obviously initial speed will be greater than final speed so u subtract u^2 from v^2 ..
do u get it?

Offline The Golden Girl =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #475 on: May 15, 2011, 10:49:36 am »
URGENT  June 2010 Q8]c)  , Edexcel By the way..

I got the S= 0.025 , t = 0.0714 , as well as the v = 0.7 , but I can't seem to get the Total distance nor total time right =.=

Thank you in advance :)

Attached.
« Last Edit: May 15, 2011, 06:47:44 pm by ~ The Golden Girl ~ »
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Offline EMO123

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Re: All Mechanics DOUBTS HERE!!!
« Reply #476 on: May 15, 2011, 11:47:36 am »
URGENT  June 2010 Q8]d)  , Edexcel By the way..

I got the S= 0.025 , t = 0.0714 , as well as the v = 0.7 , but I can't seem to get the Total distance nor total time right =.=

Thank you in advance :)

Attached.
there is no Q8 d)

Offline The Golden Girl =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #477 on: May 15, 2011, 01:00:20 pm »
I meant c)
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Offline The Golden Girl =D

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Re: All Mechanics DOUBTS HERE!!!
« Reply #478 on: May 15, 2011, 06:48:05 pm »
URGENT  June 2010 Q8]c)  , Edexcel By the way..

I got the S= 0.025 , t = 0.0714 , as well as the v = 0.7 , but I can't seem to get the Total distance nor total time right =.=

Thank you in advance :)

Attached.

Anyone  :-X
Verily, in the remembrance of Allah do hearts find rest(13:28)

Please, Don't forget to Include GG in your Prayers =D

Offline HUSH1994

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Re: All Mechanics DOUBTS HERE!!!
« Reply #479 on: May 16, 2011, 04:09:50 am »
After the string breaks the acceleration becomes 10ms^2,the distance is 1 + distance moved up in 0.5s :)