All Mechanics DOUBTS HERE!!!

[elemis]

Winter 2010

Question 4

Take moments about B.

See if the diagram helps you.

[yasser37]

Thanks a lot mate
hope that you can finish what you started 
+rep

[elemis]

Thanks a lot mate
hope that you can finish what you started 
+rep

November 09 , 52 ,Q1 <----- Not in my syllabus

June 10 , 53, Q(i) ---- A Drawing of angles taken would be greatly appreciated   What question ?

June 09, 5, Q2 (i) Same as above and Q(6) (ii)        There is no question 2 i from June 2009 and Question 6 ii is not in my syllabus.

[yasser37]

November 09 , 52 ,Q1 <----- Not in my syllabus

June 10 , 53, Q(i) ---- A Drawing of angles taken would be greatly appreciated   What question ?

June 09, 5, Q2 (i) Same as above and Q(6) (ii)        There is no question 2 i from June 2009 and Question 6 ii is not in my syllabus.

June 10 53 Question 4 part i
and I meant june 08 question 2 i

sorry for the mistake

[Sue T]

can any1 please link me to the june 2009 ms of M2 ??

[elemis]

can any1 please link me to the june 2009 ms of M2 ??

Edexcel ?

[elemis]

Here.

[Sue T]

Here.

thank you

[Sue T]

the last question in jan2010 - ques 8c - can any1 please explain?

[elemis]

The initial velocity line represents the tangent to the point at x=0.

At point Q the velocity is such that it is PERPENDICULAR to the initial velocity line.

You have to find this point Q or in other words:

Find the point alone the trajectory which has a gradient equal to the gradient of the normal (dotted red line) at point x=0.

Can you do it yourself now ?

[Sue T]

The initial velocity line represents the tangent to the point at x=0.

At point Q the velocity is such that it is PERPENDICULAR to the initial velocity line.

You have to find this point Q or in other words:

Find the point alone the trajectory which has a gradient equal to the gradient of the normal (dotted red line) at point x=0.

Can you do it yourself now ?

yesss, got it! - thank you

[elemis]

yesss, got it! - thank you

Glad to have helped.

[3bood]

jan 2011 question 6
june 2010 question 3b
jan 2010 question 7, question 8c
june 2008 question 6c
plzz guys answer ASAP, this is edexcel

[Darkstar3000]

Q 2) Two particles, P, of mass 2m, and Q, of mass m, are moving along the same straight line on a smooth horizontal plane. They are moving in opposite directions towards each other and collide. Immediately before the collision the speed of P is 2u and the speed of Q is u. The coefficient of restitution between the particles is e, where e<1. Find, in terms of u and e

(i) Speed of P after collision
(ii)Speed of Q after collision


See my situation has the balls colliding and rebounding in opposite directions but the mark scheme has them colliding and going in the same direction. How do I figure out which direction they will go in ? because I have the same answers but with different signs like my answer for (i) is u(e-1)** mark scheme has it as u(1-e). If I did this in the exam, will my answer be rejected ?

My answer for part B is correct because the direction that I chose for it is the correct one but A is wrong because of its direction

This is Jan 2010

[wakemeup]

Q 2) Two particles, P, of mass 2m, and Q, of mass m, are moving along the same straight line on a smooth horizontal plane. They are moving in opposite directions towards each other and collide. Immediately before the collision the speed of P is 2u and the speed of Q is u. The coefficient of restitution between the particles is e, where e<1. Find, in terms of u and e

(i) Speed of P after collision
(ii)Speed of Q after collision


See my situation has the balls colliding and rebounding in opposite directions but the mark scheme has them colliding and going in the same direction. How do I figure out which direction they will go in ? because I have the same answers but with different signs like my answer for (i) is u(e-1)** mark scheme has it as u(1-e). If I did this in the exam, will my answer be rejected ?

My answer for part B is correct because the direction that I chose for it is the correct one but A is wrong because of its direction

This is Jan 2010

Think about it intuitively. If one ball has a bigger mass and is moving at a faster speed than the smaller one, even though in the opposite direction, which direction will they go in? In the direction of the velocity of the ball with the bigger mass. So both will move in the same direction.