Author Topic: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !  (Read 80240 times)

Offline LekhB

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #525 on: August 31, 2012, 06:27:31 pm »
Stuck with those 3. :) If anyone could help, it'll be greatly appreciated. Thanks!





« Last Edit: August 31, 2012, 06:31:20 pm by LekhB »

Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #526 on: September 01, 2012, 07:32:26 am »
Shortly

Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #527 on: September 01, 2012, 08:16:11 am »
q6 in attachment

Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #528 on: September 01, 2012, 08:21:29 am »
q7 in attahment

Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #529 on: September 01, 2012, 08:31:36 am »
q3 in attachment

Offline sameer210394

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #530 on: October 03, 2012, 07:46:22 am »
Let 'a' and 'b' be the straight lines with equations y=m1x+c1 and y=m2x+c2 where m1m2 not equal to zero. Use appropriate trigonometric formulae to prove that 'a' and 'b' are perpendicular if and only if m1m2 = -1.
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Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #531 on: October 03, 2012, 09:59:02 am »
The trig formulae is tan
m1=tan theta 1 and m2=tan theta 2
Two lines are perprendicular is theta 2 = theta 1 +90
tan theta 2 = tan (theta 1 +90) =- 1/(tan theta 1)
so m1 m2 =tan theta 1 tan theta 2 =-1

Offline Mrsmart1017

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #532 on: October 05, 2012, 05:51:15 am »
Help pleazzz

Offline sameer210394

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #533 on: October 05, 2012, 06:47:54 am »
Use the inequality sinx < x < tanx for a suitable value of x to show that Pi lies between 3 and 2(root3)
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Offline sameer210394

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #534 on: October 05, 2012, 06:55:17 am »
p/q = root3

(cosx + sinx) / (cosx - sinx) = root3

divide numerator & denominator by cosx

(1 + tanx) / (1 - tanx) = root3

tanx = (root3 -1) / (root3 +1)

x = 15, 195
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Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #535 on: October 05, 2012, 10:23:04 am »
Use the inequality sinx < x < tanx for a suitable value of x to show that Pi lies between 3 and 2(root3)
Take x=pi/6
sin (pi/6)<pi/6<tan (pi/6)
1/2<pi/6<sqrt(3)
Multiply by 6
3<pi<2 sqrt(3)

Offline Mrsmart1017

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #536 on: October 05, 2012, 10:34:42 am »
Thanks sameer

Offline acash09

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #537 on: November 16, 2012, 07:21:42 pm »
i need help with question here, and please with full explanation if it is not too much... Thanks
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Offline astarmathsandphysics

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #538 on: November 16, 2012, 11:38:58 pm »
here

Offline whale95

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Re: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
« Reply #539 on: November 17, 2012, 08:33:20 pm »
Please check the attachments... :)