New servers, hooraaaay! More bandwidth, more power.
Done step by tiny step in attachment. Am in a slow mood.
1. The normals are n_1=(1,1,-1) and n_2=(2,-4,1)find n_1 x n_2 =(-1,-1,-6)2.-3x-3y-6z=dPut x=3,y=8, z=2 to find d=-45 so -3x-3y-6z=-45and dividing by -3 gives x+y+2z=15
P3 MJ 2008 Q3 part 1 and Q6 please
Stuck with those two: