could you pls solve this :
10sin^2(x)-5cos^2(x)+2=4sin(x)
10sin^2(x)-5cos^2(x)+2=4sin(x)
10sin^2(x)-5(1-sin^2(x))+2=4sin(x)
10sin^2(x)-5+5sin^2(x)+2=4sin(x)
15sin^2(x)-4sin(x)-3=0
solve this equation as quadratic equation
u will get
sin(x)=0.6 and sin(x)=-1/3 => 19.47
(x)=36.9 degree =180+19.47 = 199.5
(x)=143.1 degree =360-19.47 =340.5
hope u understood this piece of cake