Author Topic: C3 and C4 DOUBTS HERE!!!  (Read 35717 times)

Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #120 on: November 11, 2011, 02:04:00 pm »
Oops sorry, Its not squared just 2 theta  ::)

You are having trouble in sketching the graph then ?

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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #121 on: November 11, 2011, 02:17:54 pm »
You are having trouble in sketching the graph then ?
No, the second part i.e. finding the points
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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #122 on: November 11, 2011, 02:25:25 pm »
No, the second part i.e. finding the points

Intersection method : sin \theta = sec 2\theta

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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #123 on: November 11, 2011, 02:30:32 pm »
Intersection method : sin \theta = sec 2\theta
Lol, I know that but I need a full solution cause I got stuck in between O_O
Thanks
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Offline astarmathsandphysics

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #124 on: November 11, 2011, 02:38:28 pm »
theta =21.47 or 158.53
see attachment. Only sin theta =(-1+sqrt(3))/2 works cos(-1-sqrt(3))/2 is less than -1

Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #125 on: November 11, 2011, 03:00:27 pm »
theta =21.47 or 158.53
see attachment. Only sin theta =(-1+sqrt(3))/2 works cos(-1-sqrt(3))/2 is less than -1
Oh god, I just missed one bit O_O

Thankyou
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #126 on: November 11, 2011, 03:09:29 pm »
Another one:

Cotx = -1.5, find the value of cosecx
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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #127 on: November 11, 2011, 03:16:25 pm »
Another one:

Cotx = -1.5, find the value of cosecx

Sorry. I was late for that.

1 + cot2x = cosec2x
1 + (-1.5)2 = cosec2x
cosec x = 1.802775638 = 1.80

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Offline astarmathsandphysics

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #128 on: November 11, 2011, 03:39:47 pm »
I forgot theta=0

Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #129 on: November 19, 2011, 01:27:12 pm »
For some reason, i cant work this out or more like simplify it O_O

Differentiate (product rule): x(1 + 3x^5)
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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #130 on: November 19, 2011, 01:35:34 pm »
For some reason, i cant work this out or more like simplify it O_O

Differentiate (product rule): x(1 + 3x^5)

15x5 + 3x5
=> 18x5

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Alpha

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #131 on: November 19, 2011, 01:36:15 pm »
Angel, you must take care to differentiate what is in the bracket.

(1 + 3x^5)

Diff. but keep it in the bracket itself. Then, expand. It'll make your work easier.

Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #132 on: November 19, 2011, 01:39:35 pm »
15x5 + 3x5
=> 18x5
Lol, I said product rule ::)

The answer is --> (1 + 3x)^4 (1 + 18x)

@Alpha: Yeah but I cant seem to understand how do we end up with (1 + 18x)  :-\
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Alpha

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #133 on: November 19, 2011, 01:45:43 pm »
Lol, I said product rule ::)

The answer is --> (1 + 3x)^4 (1 + 18x)

@Alpha: Yeah but I cant seem to understand how do we end up with (1 + 18x)  :-\

x(1 + 3x^5)

x(15x^4) + ((1 + 3x^5)(1) = 18x^5 + 1.

Did you copy the question correctly?  :-\

Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #134 on: November 19, 2011, 01:47:29 pm »
^ Yeah, the question is correct.

I got the answer now  ;D

Thanks for the help anyway
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