--> C3 and C4 DOUBTS HERE!!!
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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #135 on: November 19, 2011, 02:00:45 pm »
Quote from: Ang3l on November 19, 2011, 01:39:35 pm
Lol, I said product rule ::)

The answer is --> (1 + 3x)^4 (1 + 18x)

@Alpha: Yeah but I cant seem to understand how do we end up with (1 + 18x)  :-\

Yes, I did with the product rule. I took 3x5 instead of 3x5 + 1 (which was a mistake I made). Isn't the answer 18x5 + 1 correct ?
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #136 on: November 19, 2011, 02:10:01 pm »
^ Okay, people don't KILL me ::)

I posted the question in a wrong way.
The question was: x(1 + 3x)^5 and not x(1 + 3x^5)  :-[

Sorry O_O, I got the answer By the way.

Thanks
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Re: C3 and C4 DOUBTS HERE!!!
« Reply #137 on: November 19, 2011, 02:24:31 pm »
LOL, Angel. You cannot be killed. You are an Angel. :P
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #138 on: November 19, 2011, 02:42:19 pm »
Quote from: ~Alpha on November 19, 2011, 02:24:31 pm
LOL, Angel. You cannot be killed. You are an Angel. :P
Aww, you are just so sweet that's why :D. I am not sure about anse :P*He will surely kill me now* ::)

Okay, I have another question

If we have something like (attached) and then we are supposed to take 3(2x + 1) ^(-0.5) as common then shouldnt the remaining be [x + (2x + 1)^-1]
 :-\

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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #139 on: November 19, 2011, 02:45:05 pm »
Quote from: Ang3l on November 19, 2011, 02:42:19 pm
Aww, you are just so sweet that's why :D. I am not sure about anse :P*He will surely kill me now* ::)

Okay, I have another question

If we have something like (attached) and then we are supposed to take 3(2x + 1) ^(-0.5) as common then shouldnt the remaining be [x + (2x + 1)^-1]
 :-\

Was just about to but then I realized what will I get by killing an angel. ::)

Where is the attached part ?
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #140 on: November 19, 2011, 02:50:56 pm »
^ My wings ::)

Something is wrong with me today :o

Attached it now
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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #141 on: November 19, 2011, 03:44:03 pm »
Quote from: Ang3l on November 19, 2011, 02:50:56 pm
^ My wings ::)

Something is wrong with me today :o

Attached it now

How does it feel to be a fallen angel ? Your wings are lying on the ground. How does it feel to be a fallen angel ? Forever is a long way down. :P

No, what you said is incorrect.
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #142 on: November 19, 2011, 04:34:20 pm »
Quote from: Arthur Bon Zavi on November 19, 2011, 03:44:03 pm
How does it feel to be a fallen angel ? Your wings are lying on the ground. How does it feel to be a fallen angel ? Forever is a long way down. :P

No, what you said is incorrect.

Lol.

What is the correct answer then  ::)
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Offline astarmathsandphysics

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #143 on: November 19, 2011, 09:12:17 pm »
There is nothing in common there because the powers are not the same.
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Offline Arthur Bon Zavi

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #144 on: November 20, 2011, 05:10:00 am »
Quote from: astarmathsandphysics on November 19, 2011, 09:12:17 pm
There is nothing in common there because the powers are not the same.

All in my head. ::)
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #145 on: November 20, 2011, 03:03:04 pm »
Quote from: astarmathsandphysics on November 19, 2011, 09:12:17 pm
There is nothing in common there because the powers are not the same.
What about the (2x + 1)^(0.5), is that not common?  :-\
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Offline astarmathsandphysics

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #146 on: November 20, 2011, 10:56:56 pm »
Because the power of one of them is negative, so is the same as 1/(2x+1)^(0.5)
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Offline WARRIOR

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #147 on: December 14, 2011, 07:47:51 am »
COS ( 2x + PIE/3) + COS (2x - PIE/3 ) = COS2X

how is the above proven :O?
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Offline astarmathsandphysics

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #148 on: December 14, 2011, 03:17:44 pm »
cos2xcos pi/3 -sin2x sin pi/3 +cos 2x cos pi/3 +sin 2x sin pi/3 = 2cos 2x cos pi/3 =cos 2x because cos pi/3 =1/2
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Offline Malak

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Re: C3 and C4 DOUBTS HERE!!!
« Reply #149 on: January 14, 2012, 04:16:08 pm »
Anyone?

I get the first step but then i am confused as to how they simplfy the numerator to 8 O_O
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