IGCSE MATHS Doubts

[Shazizzzle]

Shaz 1 final thing say if I take the coefficient of x to 5, then it'll p=2.5 and q= -14.25 right?

By the way, SAR right guess .

Yes. That's correct.
Don't ask me how. Naeem did it like this. On one of the days you were absent.

haha. you've used deadman786 on chappa too

[the_grim_reaper]

I did it in my copy but I couldn't read my writing . One more thing, if coefficient of x^2 isn't 1 then we first divide every number in the eq. by it??

[Shazizzzle]

I did it in my copy but I couldn't read my writing . One more thing, if coefficient of x^2 isn't 1 then we first divide every number in the eq. by it??

Yes, the whole thing, I believe, just like completing square method.

[Shazizzzle]

Plzzz help me here! :-S

Umm, parallel lines have the same gradient i.e coefficient of x. So... m=2.
3 is the y intercept. So, B (0, 3)

AB is 7.
7-3 = 4.
So, at B, y value is -4.
So c= -4

y=mx + c
y=2x -4

[Shazizzzle]

SORRY, 2nd line, So, A (0, 3) [not B]

[polltery]

yup! got it.. Thanks Shazizzzle!

[dsiddiqi11]

guys i dont get one thing, i still have a bit of a problem in shading unwanted region, i always get them right but dont knw how, lol. can someone plzz explain this linear programming stuff!!!!!!

[astarmathsandphysics]

Simple answer - it is usually a triangle so after you have drawn the lines, look for a triangle

[dsiddiqi11]

Simple answer - it is usually a triangle so after you have drawn the lines, look for a triangle

ya i knw but there could be more than one triangle, so the problem is which region to shade, so can u give me an example and briefly explain it plzzz Thanks, and By the way do u have to draw the lines or the shape is given to us

[6394]

5/8x^3/2<divided by>1/2x^-5/2
<o/n 09 ques 4>
answer this plz

[6394]

with full steps please thks in advace

[holtadit]

How would you do this.

The MS says 5k.

[Vin]

5
-- x^3/2 *  2 x^5/2
8

For this when u reciprocate 1/2x^-5/2
u get 2x and +ve x^5/2 and the sign changes to multiplication..

for eg (1/2)^-1  is simply 2 .. same rule applies here

so u get
5
-- x^3/2  *  2x ^ 5/2
8

on adding the powers (as 5/8 x  and 2 x are multiplied) and simplifying

u get

5
-- x⁴
4

[Baladya]

GUYSSS PLZZZZ HELPPP!!!!

There are 10^9 nanoseconds in 1 second.
Find the number of nanoseconds in 5 minutes, giving your answer in standard form.

I multiply 10^9 x 5 x 60 = My calculator say 3x10^12. But in mark scheme its 3x10^11?

Plz help :S :S

[contraentry]

5^y X 5¹ = 5^y+1   (Law of indices)

Therefore : 5^y= K, Hence K*5¹

Thus the answer derived is = 5k

By the way, Which paper is this question from?