Author Topic: IGCSE MATHS Doubts  (Read 130466 times)

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #150 on: May 07, 2010, 07:32:58 pm »
can u explain it .....y is da scale factoe -ve wen we move da image to left.....nd is this rule same 4 all quadrants? wat abt 3rd quadrant......wat if da image is on x-axis.....nd wat abt stretch( wen is its scale factor -ve).....thnkx.

actually even im kinda confused regarding this topic ..   :-\
the thing is i saw this rule noted in my text book while referring it ..
my teacher might hav told it in class ..
i hav emailed her about this i should get her reply soon ..  :)

Offline astarmathsandphysics

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Re: IGCSE MATHS Doubts
« Reply #151 on: May 07, 2010, 09:12:10 pm »
If this is about negative scale factors, this is one of the things I have to do on my website. A lot has gone wrong in last few days. I had to recover a hard disk with the vital data.

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #152 on: May 08, 2010, 07:18:29 am »

Thank you .. im looking forward to have them :)

Offline PeaceMaker

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Re: IGCSE MATHS Doubts
« Reply #153 on: May 08, 2010, 07:53:48 am »
Could someone be kindly to explain to me the upper bounds and lower bounds in detail? Im kinda am confused about them, but if you have notes about them then feel free to pass them on to your fellow SF mate.

Offline astarmathsandphysics

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Re: IGCSE MATHS Doubts
« Reply #154 on: May 08, 2010, 07:57:22 am »
astarmathsandphysics.com>igcse maths notes>maximising and minising

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #155 on: May 08, 2010, 08:59:38 am »
Could someone be kindly to explain to me the upper bounds and lower bounds in detail? Im kinda am confused about them, but if you have notes about them then feel free to pass them on to your fellow SF mate.

ALWAYS remember ..

for addition and multiplication ..

LB = LB + LB

LB = LB x LB

UB = UB + UB

UB = UB x UB

for subtraction or division .. (is different)
LB = LB - UB

LB = LB/UB

UB = UB - LB

UB = UB/LB  :)

consider solving some sums u'll get them  :).. these kinda ques usually appear in paper 2 .. (jus solved a couple of them few mins ago)

Offline Dark Prince

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Re: IGCSE MATHS Doubts
« Reply #156 on: May 08, 2010, 01:23:04 pm »
actually even im kinda confused regarding this topic ..   :-\
the thing is i saw this rule noted in my text book while referring it ..
my teacher might hav told it in class ..
i hav emailed her about this i should get her reply soon ..  :)


thnkxx....

Offline Fastal

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Re: IGCSE MATHS Doubts
« Reply #157 on: May 08, 2010, 01:53:30 pm »
2005 Oct/Nov
Paper 4, IGCSE

2(d)(iii)
I don't understand how you find the invariant line.
« Last Edit: May 08, 2010, 01:58:24 pm by Fastal »

Offline Snake

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Re: IGCSE MATHS Doubts
« Reply #158 on: May 08, 2010, 01:56:54 pm »
Which Paper?
-Once the game is over,the king and the pawn go back in the same box-

Offline Fastal

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Re: IGCSE MATHS Doubts
« Reply #159 on: May 08, 2010, 02:02:13 pm »
Another transformation question

3(a)(iv)[2005 June Paper 4(Igcse)]

How do you find the invariant line for the shear?


I actually have this doubt with stretch and shear(finding invariant line), when the image and object share no points.

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #160 on: May 08, 2010, 03:35:13 pm »
2005 Oct/Nov
Paper 4, IGCSE

2(d)(iii)
I don't understand how you find the invariant line.

it might take me a lot of time .. havta solve the whole ques!!

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #161 on: May 08, 2010, 04:08:31 pm »
2005 Oct/Nov
Paper 4, IGCSE

2(d)(iii)
I don't understand how you find the invariant line.

About invariant lines .. for stretch, the transformation takes place perpendicular to the invariant line .. ;)

Offline ksitna

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Re: IGCSE MATHS Doubts
« Reply #162 on: May 08, 2010, 04:11:01 pm »
how to simplify

x-3= 4
4     x-3
take whatever you want and give nothing back :)

Offline Vin

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Re: IGCSE MATHS Doubts
« Reply #163 on: May 08, 2010, 04:19:20 pm »
how to simplify

x-3= 4
4     x-3

sorry i didnt get the ques ???

Offline @d!_†oX!©

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Re: IGCSE MATHS Doubts
« Reply #164 on: May 08, 2010, 04:21:05 pm »
is it,
(x-3)/4 = 4/(x-3)
then,
=> (x-3)(x-3) = 4*4
=> x2 -6x +9 = 16
=> x2 -6x -7 = 0
=> (x+1)(x-7) = 0
=> x = -1 , x = 7
AAL IZZ WELL!!! ;)