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are u referring at me? question 7 is about vector :/
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w10_ms_31.pdfhow to do question 7 part ii?
as for the second partlisten when there is a equation like y^2/y^3+1 the only way to integrate this is when you differentiate the denominator the exact value should come in the numerator. In this case the differentiation of y^3+1 is 3y^2 but in the numerator it is y^2 so you take the 3 out by multiplying it by 1/3. so now it comes 1/3(y^2/y^3+1)and then you get 1/3ln(y^3+1)
so i am kinda right?
Yes sir/Madam.
so how do you get the greatest arg value and least too?
Please correct me if i am wrong.
By the way, how do u know its half?
Sorry I did a mistake. Should have taken radius as one unit.yeah so check the x and y values for the lowest point y/x will give you tan of the argument
