Author Topic: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !  (Read 77764 times)

Offline leebux101

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #360 on: May 18, 2011, 06:12:15 pm »
yeah ok thanks alot, the earlier attachment that u posted, thats also right,  ryt?

Offline leebux101

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #361 on: May 18, 2011, 06:13:00 pm »
also can u please do ON2010 Q1 from P32! please! please please!
ur a life saver!

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #362 on: May 18, 2011, 06:13:35 pm »
I just showed how to find the modulas of the least argument .

Offline SkyPilotage

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #363 on: May 18, 2011, 06:14:24 pm »
also can u please do ON2010 Q1 from P32! please! please please!
ur a life saver!

Just square both sides..

Offline SkyPilotage

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #364 on: May 18, 2011, 06:17:10 pm »
This was the second part.


Actually you solved it correctly the first time...
The least value for modulus of z is where the line from the origin intersets the circle closest to the origin which is somewhere at the centre of the circle.. Check the diagram you drew again.. And isnt the modulus of u is root 2 not 2root2?

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #365 on: May 18, 2011, 06:18:31 pm »
Just square both sides..
and to find the range
just put the values -7 and 1 on a number line

take out any value less than 1 like 0 and put it into (x-1)(x+7)
take out another value between -7 and 1 and put it into ^

and finally a value less than -7 and put it into (x-1)(x+7)

and see if they are less than 0

Offline leebux101

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #366 on: May 18, 2011, 06:20:54 pm »
yeah what u did earlier was ryt too..
and the answer is the same in the marking scheme


secondly >> i did square the sides! =( but i dont get it,
can u give a step by step description please! please! =(

Offline leebux101

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #367 on: May 18, 2011, 06:21:56 pm »
and to find the range
just put the values -7 and 1 on a number line

take out any value less than 1 like 0 and put it into (x-1)(x+7)
take out another value between -7 and 1 and put it into ^

and finally a value less than -7 and put it into (x-1)(x+7)

and see if they are less than 0
hey i didnt know we could do that... interesting..

........

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #368 on: May 18, 2011, 06:22:45 pm »
Actually you solved it correctly the first time...
The least value for modulus of z is where the line from the origin intersets the circle closest to the origin which is somewhere at the centre of the circle.. Check the diagram you drew again.. And isnt the modulus of u is root 2 not 2root2?


dude they're not asking for least value of modulus of z
they're asking for modulus of z when argument of z is least

Offline SkyPilotage

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #369 on: May 18, 2011, 06:23:49 pm »

dude they're not asking for least value of modulus of z
they're asking for modulus of z when argument of z is least

which question are you on? ahaha

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #370 on: May 18, 2011, 06:26:11 pm »
Hi guys
I really need help with complex numbers and argand diagrams!
Can u plz help me with these qs/

JUNE 10 V1 Q7 Part 3
THANK U


This one
I am getting confused bro..
There were 3 questions that were being asked

Offline SkyPilotage

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #371 on: May 18, 2011, 06:26:53 pm »
and to find the range
just put the values -7 and 1 on a number line

take out any value less than 1 like 0 and put it into (x-1)(x+7)
take out another value between -7 and 1 and put it into ^

and finally a value less than -7 and put it into (x-1)(x+7)

and see if they are less than 0
Would be easier for you if you say that outside the range, the sign is the same sign as a(coefficient of x^2) so if its <0 then its  -7<x<1 ...
But your way is perfectly correct too...

Offline SkyPilotage

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #372 on: May 18, 2011, 06:27:50 pm »
This one
I am getting confused bro..
There were 3 questions that were being asked
OH oH my bad!! I thought you were on Nov 2006  9 iii) it has also u and z-u=1 srry :D

Offline leebux101

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #373 on: May 18, 2011, 06:28:45 pm »
oh never mind! i thought u were talking about ON 2003 question..
guys please i need this one ON 2010 P32 Q1

Offline leebux101

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Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #374 on: May 18, 2011, 06:29:38 pm »
confusion between 3 papers! lol haha! =D