Author Topic: [CIE] All Pure Mathematics (P1, P2 and P3) doubts here !  (Read 79965 times)

Offline melony

  • SF Immigrant
  • **
  • Posts: 118
  • Reputation: 131
  • Gender: Female
  • i got fruit by that foot in mah fruit rollup <3
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #330 on: May 18, 2011, 12:35:37 am »
awh no :-\! seems like everyone's offline, i just had two questions:
ON10 paper 31 question 7 (ii) i do not know how to get ?=-1/6  :(
June 2004 question 6 - i know it starts of like 1/3 ln (y^3+1)=x+c but i have no idea where the 1/3 comes from (should have listened in class  :'()
xOx

........

  • Guest
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #331 on: May 18, 2011, 01:47:21 am »
awh no :-\! seems like everyone's offline, i just had two questions:
ON10 paper 31 question 7 (ii) i do not know how to get ?=-1/6  :(
June 2004 question 6 - i know it starts of like 1/3 ln (y^3+1)=x+c but i have no idea where the 1/3 comes from (should have listened in class  :'()

Um i just did Oct/Nov 2010 so yea heres your solution to 2010 query

........

  • Guest
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #332 on: May 18, 2011, 02:00:03 am »
can someone explain how to do questions like -->
question 5 paper 33 june 2010 part ii
and
question 3 paper 33 octover/nov 2010 part ii


and how to do question 10 on may june 2010 paper 33
Thank you very much

Modulas 5 is the radius and (3,4) is the center of the circle and you have to shade all the points on and inside the circle center.October/November 2010 part ii

Offline leebux101

  • SF Geek
  • ****
  • Posts: 495
  • Reputation: 2966
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #333 on: May 18, 2011, 02:03:40 am »
awh no :-\! seems like everyone's offline, i just had two questions:
ON10 paper 31 question 7 (ii) i do not know how to get ?=-1/6  :(
June 2004 question 6 - i know it starts of like 1/3 ln (y^3+1)=x+c but i have no idea where the 1/3 comes from (should have listened in class  :'()
for june 2004,
u get y2ln(y3 +1)
so when differentiating the inner content, u get y3ln(y3 +1)/3y2
y2 gets cancelled and u get u 1/3 ln(y3 +1)
please reconfirm this cud i am not sure if i am right..
can anyone reconfirm this.. ? pleaseeee!!! =(

Offline leebux101

  • SF Geek
  • ****
  • Posts: 495
  • Reputation: 2966
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #334 on: May 18, 2011, 02:04:39 am »
Its A circle with radius=2 units and center u.
i wrote part iii not part ii, do u know part iii then?

........

  • Guest
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #335 on: May 18, 2011, 02:26:38 am »
can someone explain how to do questions like -->
question 5 paper 33 june 2010 part ii
and
question 3 paper 33 octover/nov 2010 part ii


and how to do question 10 on may june 2010 paper 33
Thank you very much
question 5 paper 33 june 2010 part ii


........

  • Guest
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #336 on: May 18, 2011, 02:35:13 am »
awh no :-\! seems like everyone's offline, i just had two questions:
ON10 paper 31 question 7 (ii) i do not know how to get ?=-1/6  :(
June 2004 question 6 - i know it starts of like 1/3 ln (y^3+1)=x+c but i have no idea where the 1/3 comes from (should have listened in class  :'()

as for the second part

listen when there is a equation like y^2/y^3+1 the only way to integrate this is when you differentiate the denominator the exact value should come in the numerator. In this case the differentiation of y^3+1 is 3y^2 but in the numerator it is y^2 so you take the 3 out by multiplying it by 1/3. so now it comes 1/3(y^2/y^3+1)and then you get 1/3ln(y^3+1)

Offline melony

  • SF Immigrant
  • **
  • Posts: 118
  • Reputation: 131
  • Gender: Female
  • i got fruit by that foot in mah fruit rollup <3
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #337 on: May 18, 2011, 08:08:57 am »
wow thank you guys so much (leebux101 and ........)!!   :D
i wish you well for the exam  :)
xOx

Offline TJ-56

  • SF Citizen
  • ***
  • Posts: 192
  • Reputation: 1969
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #338 on: May 18, 2011, 08:21:33 am »
That is because if you substitute t=-2 and t=-1/3 in the position vector of P ; the dot product of AP.AB should be +ve since the angle is acute.. If its -ve the angle is obtuse...Therefore if you use t=-2 you will get it +ve, and t=-1/3 will be -ve meaning obstuse angle which is incorrect..

Oh ok thanx.. that cleared it up,
+rep

Offline aloha32

  • Newbie
  • *
  • Posts: 12
  • Reputation: 22
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #339 on: May 18, 2011, 08:42:46 am »
Hi guys
I really need help with complex numbers and argand diagrams!
Can u plz help me with these qs/
 Nov 06 q9 part 4
Nov 09 q7 part4
JUNE 10 V1 Q7 Part 3
THANK U

Offline SkyPilotage

  • SF Citizen
  • ***
  • Posts: 184
  • Reputation: 65535
  • Gender: Male
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #340 on: May 18, 2011, 09:47:38 am »
Hi guys
I really need help with complex numbers and argand diagrams!
Can u plz help me with these qs/
 Nov 06 q9 part 4
Nov 09 q7 part4
JUNE 10 V1 Q7 Part 3
THANK U

Sadly , i dont have a good scanner to show you the argand diagrams :( So hopefully someone will upload them for you...
Who has the Alevel Cie Pure mathematics 2 and 3 by Hugh Neil and Douglas Quading???
Page 300 number 6 I) and page 303 number 9I)

Offline Arthur Bon Zavi

  • |Sun of Tomorrow... =]|
  • SF V.I.P
  • ********
  • Posts: 5849
  • Reputation: 65041
  • Gender: Male
  • Fiducia in questo uomo ciecamente.
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #341 on: May 18, 2011, 12:12:08 pm »
Sadly , i dont have a good scanner to show you the argand diagrams :( So hopefully someone will upload them for you...
Who has the Alevel Cie Pure mathematics 2 and 3 by Hugh Neil and Douglas Quading???
Page 300 number 6 I) and page 303 number 9I)

Me. :P

Continuous efforts matter more than the outcome.
- NU

........

  • Guest
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #342 on: May 18, 2011, 01:47:36 pm »
Hi guys
I really need help with complex numbers and argand diagrams!
Can u plz help me with these qs/
 Nov 06 q9 part 4
Nov 09 q7 part4
JUNE 10 V1 Q7 Part 3
THANK U


for November 06
Find the modulas of Ou which is SQR(2) and the modulas of the point (1,0) on the x axis which is 1.

therefore the least value of |z|=SQR(2)-1=0.414

Offline physichemaths

  • Newbie
  • *
  • Posts: 26
  • Reputation: 37

Offline physichemaths

  • Newbie
  • *
  • Posts: 26
  • Reputation: 37
Re: All Pure Mathematics DOUBTS HERE!!!
« Reply #344 on: May 18, 2011, 02:17:30 pm »
I am not sure but i think this is the solution to part ii

are u referring at me? question 7 is about vector :/