January 2010 Question 7 (d)
Find the area underneath the curve between (4,0) and (5,0)
Because this area in combination with the region are will make a triangle.
![\int_{4}^{5}(x^2-5x+4)=\frac{11}{6}](https://studentforums.biz/cgi-bin/mimetex.cgi?\int_{4}^{5}(x^2-5x+4)=\frac{11}{6})
The area of the triangle is
![\frac{1}{2}*4*4=8](https://studentforums.biz/cgi-bin/mimetex.cgi?\frac{1}{2}*4*4=8)
So, now simply take away the excess region from the triangle.
![8-\frac{11}{6}=6\frac{1}{6}](https://studentforums.biz/cgi-bin/mimetex.cgi?8-\frac{11}{6}=6\frac{1}{6})