ammeter reads 2A
if lamp N removed the current in ammeter become less than 2A explain why???
sorry for poor drawing
Lamp M and N are connected in parallel.
In parallel circuits,
1-voltage is the same across each resistance, which means if the the power supply is 2v, both lamp M and N will get a 2V supply.
2-Total current supplied by the battery is equal to the sum of currents passing through each resistance or branch of the circuit.
Which means Total current = lamp M current + lamp N current
3-Total resistance of the circuit = 1/R1 + 1/R2
When lamp N is removed, we get a series circuit,
In series circuits,
1- Total volatge = V1+v2+v3
2- Total resistance = R1+R2+R3
3- Same current flows through each resistance
Lamps M and N are identical, both need same current, e.g 1A for each
when M and N are connected in PARALLEL, current= 1+1 = 2A
When only M is connected, Current= 1A
and if M and N were connected in SERIES then Current = 1A
Hope this helps
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