IGCSE PHYSICS DOUBTS HERE !!!!

[SauD~]

Anymore?
Were those clear?

[~ Miss Relina ~]

Anymore?
Were those clear?

ya Thanks they were clear now i have others hope u can help with
A man jumps from an aeroplane. He falls freely
what happens to him when his parachute opens?
1.he begins to move upwards
2.he contiues falling but at a slower speed
choose one and explain why??
thxnin advance

[~ Miss Relina ~]

ammeter reads 2A
if lamp N removed the current in ammeter become less than 2A explain why???
sorry for poor drawing

[~ Miss Relina ~]

when goalkeeper punches the ball over the bar,what happens to the ball as its bunched ??
answer says it changes both shape and direction why why

[SauD~]

ya Thanks they were clear now i have others hope u can help with
A man jumps from an aeroplane. He falls freely
what happens to him when his parachute opens?
1.he begins to move upwards
2.he contiues falling but at a slower speed
choose one and explain why??
thxnin advance

2nd one because when he opened the parachute, the air resistance caused by it makes it equal to the pull of gravity. So his speed gets slow

[SauD~]

when goalkeeper punches the ball over the bar,what happens to the ball as its bunched ??
answer says it changes both shape and direction why why

When ever force is applied to an object, it would change its shape, direction and speed.
Force always do that

[SauD~]

ammeter reads 2A
if lamp N removed the current in ammeter become less than 2A explain why???
sorry for poor drawing

I am not so sure about this one
Maybe its something:
Currents gets divided into half in a parallel,
M lamp takes more current and in parallel it receive the half amount of current, while in series t consume more of current
I am not sure

[elemis]

ammeter reads 2A
if lamp N removed the current in ammeter become less than 2A explain why???
sorry for poor drawing

The ammeter reads a value of 2 amps since 2 amps are 'consumed' by the two lamps.

Lets say lamp M needs 1.8 amps and N neds 0.2, thus when N is removed only 1.8 amps are supplied by the battery as only M is left.

Thus, the ammeter reads 1.8 amps.

[~ Miss Relina ~]

The ammeter reads a value of 2 amps since 2 amps are 'consumed' by the two lamps.

Lets say lamp M needs 1.8 amps and N neds 0.2, thus when N is removed only 1.8 amps are supplied by the battery as only M is left.

Thus, the ammeter reads 1.8 amps.

Thanks for the idea but i;m soorry tht i didnot mention in my previuos posts that in the question they said that the two lamps were identical so does the same idea apply
and plz do u think that when a 2A are supplied by the battery whatever lamps was there or it depends on the resistance each lamp has  

[~ Miss Relina ~]

hey guys i 've been waitin fir 10 days 

[The Golden Girl =D]

I'm sorry but what is it that you're waiting for ? .. Please Quote your post that hasn't been answered.

[Most UniQue™]

Thanks for the idea but i;m soorry tht i didnot mention in my previuos posts that in the question they said that the two lamps were identical so does the same idea apply
and plz do u think that when a 2A are supplied by the battery whatever lamps was there or it depends on the resistance each lamp has  

This is the question

[NotAbod]

ammeter reads 2A
if lamp N removed the current in ammeter become less than 2A explain why???
sorry for poor drawing

Lamp M and N are connected in parallel.
In parallel circuits,
1-voltage is the same across each resistance, which means if the the power supply is 2v, both lamp M and N will get a 2V supply.
2-Total current supplied by the battery is equal to the sum of currents passing through each resistance or branch of the circuit.
Which means Total current = lamp M current + lamp N current
3-Total resistance of the circuit = 1/R1 + 1/R2

When lamp N is removed, we get a series circuit,
In series circuits,
1- Total volatge = V1+v2+v3
2- Total resistance = R1+R2+R3
3- Same current flows through each resistance

Lamps M and N are identical, both need same current, e.g 1A for each
when M and N are connected in PARALLEL, current= 1+1 = 2A
When only M is connected, Current= 1A
and if M and N were connected in SERIES then Current = 1A

Hope this helps
If ur still facing problems, then PM me

[~ Miss Relina ~]

Lamp M and N are connected in parallel.
In parallel circuits,
1-voltage is the same across each resistance, which means if the the power supply is 2v, both lamp M and N will get a 2V supply.
2-Total current supplied by the battery is equal to the sum of currents passing through each resistance or branch of the circuit.
Which means Total current = lamp M current + lamp N current
3-Total resistance of the circuit = 1/R1 + 1/R2

When lamp N is removed, we get a series circuit,
In series circuits,
1- Total volatge = V1+v2+v3
2- Total resistance = R1+R2+R3
3- Same current flows through each resistance

Lamps M and N are identical, both need same current, e.g 1A for each
when M and N are connected in PARALLEL, current= 1+1 = 2A
When only M is connected, Current= 1A
and if M and N were connected in SERIES then Current = 1A

Hope this helps
If ur still facing problems, then PM me

Thanks for u Life Saver
i'll be always wait for ur convincing for ur convincing answers

[NotAbod]

Thanks for u Life Saver
i'll be always wait for ur convincing for ur convincing answers

Your most welcome
2 times " for ur convincing" ?