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Author Topic: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE  (Read 18045 times)

Offline Meticulous

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #15 on: June 03, 2010, 01:26:49 pm »
Have you calculated the momentum before and after the collision? What were your answers?
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #16 on: June 03, 2010, 01:32:52 pm »
Quote from: ~ A.F ~ on June 03, 2010, 01:26:49 pm
Have you calculated the momentum before and after the collision? What were your answers?

nop i calculated the change in momentum, its 0.14
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Offline Meticulous

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #17 on: June 03, 2010, 01:34:02 pm »
Well then..

its not conserved

right?
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #18 on: June 03, 2010, 01:43:52 pm »
Quote from: ~ A.F ~ on June 03, 2010, 01:34:02 pm
Well then..

its not conserved

right?

 actually the ms says :
plate (and Earth) gain momentum
equal and opposite to the change for the ball
so momentum is conserved


and sorry that was change in energy not momentum  ;D
we didnt have to  calculate momentum
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Offline Meticulous

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #19 on: June 03, 2010, 01:52:13 pm »
LOL no prblm

The thing is..mometum is like energy...always conserved.

The q here was tricky, to the ball, it LOST momentum..but still the lost momentum went to earth

so basically its conserved

Right?
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #20 on: June 03, 2010, 01:59:42 pm »
Quote from: ~ A.F ~ on June 03, 2010, 01:52:13 pm
LOL no prblm

The thing is..mometum is like energy...always conserved.

The q here was tricky, to the ball, it LOST momentum..but still the lost momentum went to earth

so basically its conserved

Right?

alright ;)
thx ;)
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everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline Meticulous

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #21 on: June 03, 2010, 02:03:01 pm »
Any time.
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #22 on: June 04, 2010, 04:16:31 pm »
2003 nov
Q3ci
is it towards or away from the disc?

Q4biii
is there a specific formula here or wat?
« Last Edit: June 04, 2010, 04:45:57 pm by halosh92 »
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nid404

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #23 on: June 04, 2010, 04:45:52 pm »
Quote from: halosh92 on June 04, 2010, 04:16:31 pm
2003 nov
Q3ci
is it towards or away from the disc?

away from the disc
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #24 on: June 04, 2010, 04:48:39 pm »
Quote from: nid404 on June 04, 2010, 04:45:52 pm
away from the disc

how do we know  ???
and could u do the other question too?
thx  :)
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nid404

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #25 on: June 04, 2010, 05:00:08 pm »
It forms a couple. Forces will act away from each other.

I'll be back after dinner  :)
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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #26 on: June 04, 2010, 05:02:46 pm »
Quote from: nid404 on June 04, 2010, 05:00:08 pm
It forms a couple. Forces will act away from each other.

I'll be back after dinner  :)

ooh ::)
thx nid  ;D
also Q5c  shouldnt be a straight CONSTANT line...as velocity is dependent on voltage which is unaltered in this case ? ???
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nid404

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #27 on: June 04, 2010, 06:35:29 pm »
4)b)iii) You use the formula
\lambda=ax/D

a=slit width
x=1/2 L
D= distance from screen
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nid404

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #28 on: June 04, 2010, 06:42:24 pm »
5)c) Depends on the force i guess. I'm not too sure if the graph would be a linear straight line or whether it would be constant. Cause electric field strength is constant

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Offline halosh92

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Re: P.H.Y.S.I.C.S P2 D.O.U.B.T.S CIE
« Reply #29 on: June 04, 2010, 06:51:18 pm »
Quote from: nid404 on June 04, 2010, 06:42:24 pm
5)c) Depends on the force i guess. I'm not too sure if the graph would be a linear straight line or whether it would be constant. Cause electric field strength is constant



the ms says its a curve :S
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