Author Topic: Edexcel CHEMISTRY DOUBTS!!!!  (Read 246727 times)

Offline Weaam

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #720 on: January 12, 2011, 05:23:40 pm »
It's C because first you find the number of moles of each of the solution by n = c x v then multiply the number of ions into the number of moles (n). A and B have 2 ions so x 2. C and D have 3 ions so x 3. A, B and D have the final answer = 2 but C = 3 so the answer is C.  Hope you understand. :)
I did thankss ;D
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Can anyone help with this Q
thx
Ill help you with that tomorrow, cant think right now, headachee D:
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Offline Weaam

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #721 on: January 12, 2011, 05:25:29 pm »
Can anyone tell me if ur calculating the enthalpy of combustion and formation which one is, enthalpy of produts - enthalpy of reactants
and which one is enthalpy of reactants - enthalpy of products
Thankss
- The man who smiles when things go wrong has thought of someone to blame it on. - Robert Bloch.
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Offline The Golden Girl =D

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #722 on: January 12, 2011, 08:36:54 pm »
Can anyone tell me if ur calculating the enthalpy of combustion and formation which one is, enthalpy of produts - enthalpy of reactants
and which one is enthalpy of reactants - enthalpy of products
Thankss

formation ,going upwards ; FORMATION = products - reactants

Combustion , going downwards ; COMBUSTION = reactants - products

I can't seem to get what Polar and Non-Polar mean  :-\ :-X

thanks in advance =]
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Offline Amii

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #723 on: January 12, 2011, 08:42:33 pm »

I can't seem to get what Polar and Non-Polar mean  :-\ :-X

thanks in advance =]

GG Check this link - might help  :)
http://users.stlcc.edu/gkrishnan/polar.html

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #724 on: January 12, 2011, 09:00:09 pm »
Verily, in the remembrance of Allah do hearts find rest(13:28)

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Offline Amii

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #725 on: January 12, 2011, 09:17:52 pm »

By my sweeett nephew ;D

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #726 on: January 13, 2011, 02:29:27 pm »
Can anyone help with this Q
thx

Well according to the stoichiometric coefficient, there is only one mol of Mg in a molecule of chlorophyll. Therefore, there is
1.20 nanmol-3 of Mg present. Simply multiply the molecular mass of Mg (24.32 g/mol) by this number of moles to get your answer in grams.

Offline Helium

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #727 on: January 15, 2011, 12:50:27 pm »
Question plz :D

Name and draw the following compounds,

1.CH3CHCHCH2CH(C2H5)CH3

2,CH3CH2C(CH3)2CH2CH(C3H7)CH2CH3

I can easily draw but the 6 nomenclature rules don't seem to work or
i don't get them good yet, when explaining can you say why, and whats
meant by substituent group,
Aiming for the top

Offline Amii

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #728 on: January 15, 2011, 02:14:16 pm »
Question plz :D

Name and draw the following compounds,

1.CH3CHCHCH2CH(C2H5)CH3

2,CH3CH2C(CH3)2CH2CH(C3H7)CH2CH3

I can easily draw but the 6 nomenclature rules don't seem to work or
i don't get them good yet, when explaining can you say why, and whats
meant by substituent group,
CH3CHCHCH2CH(C2H5)CH3 - For this you are sure that there are two double bonds? Cause then it would be a diene  :-\

CH3CH2C(CH3)2CH2CH(C3H7)CH2CH3

3,3-dimethyl-5-propyl heptane

2 methyl groups(removing a hydrogen atom from a molecule of methane, CH4 gives a group of atoms CH3-, called METHYL) on the 3rd carbon thus 3,3-dimethyl

1 propyl group( removing a hydrogen atom from a molecule of propane,C3H8 gives a group of atoms C3H7-, called PROPYL )on the 5th carbon thus 5-propyl

longest parent chain consists of 7 carbons - all having single bonds - hence heptane

Number the carbon atoms from the left side - cause that's how the methyl and propyl get the lowest value

methy and propyl - according to the alphabetical order

A substituent is an atom or group of atoms substituted in place of a hydrogen atom on the parent chain of a hydrocarbon - eg the methyl group or the propyl group

I hope it's correct  :-\

Check this link - might help http://www.physchem.co.za/OB12-mat/organic2.htm

Take care  :D

« Last Edit: January 15, 2011, 02:28:42 pm by Amii »

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Offline Helium

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #729 on: January 15, 2011, 03:15:50 pm »
THANK YOU ;D
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Offline Amii

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #730 on: January 15, 2011, 06:06:58 pm »

By my sweeett nephew ;D

Offline Uchia

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #731 on: January 17, 2011, 03:37:56 pm »
plz answer the following

question 18 part c ii, iii, and iv

in edexcel unit 4 new specimen paper
I've attached the paper to

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #732 on: January 18, 2011, 06:42:59 pm »
plz answer the following

question 18 part c ii, iii, and iv

in edexcel unit 4 new specimen paper
I've attached the paper to

The answers are already given below the questions in the specimen paper. :-\

Offline Uchia

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #733 on: January 18, 2011, 08:23:04 pm »
yeah i know but i didn't understand the calculation part they didn't explain it gd in the markscheme

Offline obstacle26

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Re: Edexcel CHEMISTRY DOUBTS!!!!
« Reply #734 on: January 21, 2011, 11:07:59 pm »
From an Infrared spectrum  how to deduce where the intensity of a peak is broad,weak, medium,strong, varibale and sharp?
Can any one label it on a spectrum to make it clear?