Qualification > Math
S1 and S2 DOUBTS HERE!!!!
**RoRo**:
--- Quote from: Mr. MUST on April 11, 2011, 07:34:09 pm ---widht would be::
3*2/6 = 1 cm
and height is :
10*9/15 = 6
so 6/1 = 6 cm
SIMPLE
--- End quote ---
Can you please explain to me what those numbers mean, what does the 3, 2, 6, 10, 9 and 15 stand for? :/
I'm sorry for the trouble, but this lesson has been annoying me since the IG's!
& again, you solved the wrong question, I wanted part e not d! ;)
**RoRo**:
Okay, I've compiled my questions here in this post to make it easier! :)
1. Question 3 of June 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20June/6683%20June%202009.pdf
2. Question 3e of January 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20Jan/S1%202009-01.pdf
3. Question 7c of June 2008 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2008%20June/S1%202008-june-qp.pdf
4. Questions 6b and c of January 2008 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2008%20Jan/6683_01_que_20080115.pdf
With explanation please, I have the marking scheme, so I know the answers, but I can't understand the working/how to do it! :/
Thanks alot! :)
Arthur Bon Zavi:
--- Quote from: The Secret on April 11, 2011, 07:50:50 pm ---
Can you please explain to me what those numbers mean, what does the 3, 2, 6, 10, 9 and 15 stand for? :/
I'm sorry for the trouble, but this lesson has been annoying me since the IG's!
& again, you solved the wrong question, I wanted part e not d! ;)
--- End quote ---
Formula for
(i) frequency density (height) :
frequency
= ------------
class width
(ii) class width (interval) :
frequency
= ------------------
frequency density
Now for your question :
3 (a)
x = 10 - 15 (9.5 - 15.5); frequency = 15.
class width = (15.5 - 9.5) = 6. This is taken in histogram as 2 cm.
For 16 - 19, width is (19.5 - 16.5) = 3.
In the histogram, the width of the 16 - 18 class will be : (3 X 2)/6 = 1
(b)
Height (or frequency density) = (15 / 6) = 2.5. This is taken in histogram as 5 cm.
For 16 - 19, height is (9 / 3) = 3.
In the histogram, the height of the 16 - 18 class will be : (3 X 5)/2.5 = 6
Tell me if you still didn't get.
**RoRo**:
--- Quote from: Fidato on April 12, 2011, 09:38:02 am ---Formula for
(i) frequency density (height) :
frequency
= ------------
class width
(ii) class width (interval) :
frequency
= ------------------
frequency density
Now for your question :
3 (a)
x = 10 - 15 (9.5 - 15.5); frequency = 15.
class width = (15.5 - 9.5) = 6. This is taken in histogram as 2 cm.
For 16 - 19, width is (19.5 - 16.5) = 3.
In the histogram, the width of the 16 - 18 class will be : (3 X 2)/6 = 1
(b)
Height (or frequency density) = (15 / 6) = 2.5. This is taken in histogram as 5 cm.
For 16 - 19, height is (9 / 3) = 3.
In the histogram, the height of the 16 - 18 class will be : (3 X 5)/2.5 = 6
Tell me if you still didn't get.
--- End quote ---
Thanks a lot! :)
Alpha:
1. Question 3 of June 2009
Frequency density= Freq/ Class width
The freq. density will be the height of your histogram in case of unequal class widths.
x :10 – 15
Frequency= 15
Class width= 15 - 10 = 5
Frequency density= 15/5 = 3
Now, use proportions.
Class width, 5 : 2
Height, 3 : 5
For 16 – 18:
Class width=18 - 16 = 2
On histogram -> 2/5*2= 1/5
Frequency density=9/2 = 4.5
On histogram ->(5/3)*(9/2) = 15/2 = 7.5
I don't find the MS from your link... so, please check it.
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