Qualification > Math
S1 and S2 DOUBTS HERE!!!!
**RoRo**:
--- Quote from: ~Alpha on April 12, 2011, 05:56:55 pm ---1. Question 3 of June 2009
Frequency density= Freq/ Class width
The freq. density will be the height of your histogram in case of unequal class widths.
x :10 – 15
Frequency= 15
Class width= 15 - 10 = 5
Frequency density= 15/5 = 3
Now, use proportions.
Class width, 5 : 2
Height, 3 : 5
For 16 – 18:
Class width=18 - 16 = 2
On histogram -> 2/5*2= 1/5
Frequency density=9/2 = 4.5
On histogram ->(5/3)*(9/2) = 15/2 = 7.5
I don't find the MS from your link... so, please check it.
--- End quote ---
I'm sorry, your answers are wrong, check Fidato's post above for the right answer.
Arthur Bon Zavi:
--- Quote from: ~Alpha on April 12, 2011, 05:56:55 pm ---1. Question 3 of June 2009
Frequency density= Freq/ Class width
The freq. density will be the height of your histogram in case of unequal class widths.
x :10 – 15
Frequency= 15
Class width= 15 - 10 = 5
Frequency density= 15/5 = 3
Now, use proportions.
Class width, 5 : 2
Height, 3 : 5
For 16 – 18:
Class width=18 - 16 = 2
On histogram -> 2/5*2= 1/5
Frequency density=9/2 = 4.5
On histogram ->(5/3)*(9/2) = 15/2 = 7.5
I don't find the MS from your link... so, please check it.
--- End quote ---
Alpa, there you went wrong. Check the intervals before 16 - 18. They were 10 - 15, so in order to built a histogram, you need to amend the values to make them continuous (so you subtract 0.5 from the lower limit and add 0.5 to the upper limit).
Like take two class intervals, (10 - 15) and (16 - 18). There's gap of 1 between 15 and 16, so how can you make a histogram ?
Arthur Bon Zavi:
Doing the rest.
Arthur Bon Zavi:
--- Quote from: The Secret on April 11, 2011, 10:59:47 pm ---Okay, I've compiled my questions here in this post to make it easier! :)
--- End quote ---
Here they follow.
--- Quote ---1. Question 3 of June 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20June/6683%20June%202009.pdf
--- End quote ---
Done.
--- Quote ---2. Question 3e of January 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20Jan/S1%202009-01.pdf
--- End quote ---
After 3 games Rohit has scored 6.
2 games are left and he has to get 4 points or more to win the prize.
List all the outcomes of the points he can get (see the image below).
You can see that there are 16 possible outcomes and six of which fetch him 4 points or more.
You know that :
P(0) = 0.4
P(1) = 0.3
P(2) = 0.2
P(3) = 0.1
So to win a price he should get points with the outcomes as follows (as circled in image).
{ (1,3) (2,2) (2,3) (3,1)(3,2) (3,3) }
Multiply and add the probabilities :
(0.3 X 0.1) + (0.2 X 0.2) + (0.2 X 0.1) + (0.1 X 0.3) + (0.1 X 0.2) + (0.1 X 0.1)
= 0.03 + 0.04 + 0.02 + 0.03 + 0.02 + 0.01
= 0.15
Arthur Bon Zavi:
--- Quote ---3. Question 7c of June 2008 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2008%20June/S1%202008-june-qp.pdf
--- End quote ---
(7) (c)
For this you need to find out the probability that the bag weighs more than 53 kg.
(a)
More than 53, so (53 + 0.5 = 53.5)
53.5 - 50
Z = ------------
2
= si (1.75)
= 0.9599
Now, it's greater then 53, so :
1 - { si (1.75) }
= 1 - 0.959
= 0.0401
(c)
2 bags greater than 53 kg and 1 less than 53 kg .
Probability that any bag is greater then 53 kg = 0.0401
and
Probability that it is less then 53 kg = 0.959
So :
3C2 X (0.401)2 X (0.959)
= 0.004630586
= 0.0046
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