Qualification > Math

S1 and S2 DOUBTS HERE!!!!

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Aadeez || Zafar:

--- Quote from: The Secret on April 11, 2011, 05:45:01 pm ---Can someone please solve for me Question 3 in May 2009 with steps?

--- End quote ---
(i)
P(0 buses) = (1-0.16)11
P(1 bus) = 11C1(0.16)(1-0.16)10
P(2 buses) = 11C2(0.16)2(1-0.16)9

where X is number of buses passed

so

P(X<3)= P(0 Busus)+P(1 Buses)+P(2 buses)

(ii)

USE normal distribution


mean = np
        = 125(1-(0.16+0.2))
        = 125 (0.64)
       = 80
variance = npq
            = 125 (0.64)(1-0.64)
             = 28.8
let X be number of car passed

so

p(X>73)
= 1-P(X<=73)
=1 - ?((73-80)/root(28.8)
=1-?(-1.304)
=1-(1-?(1.304))
=1-1+?(1.304)
= ?(1.304)

use normal distribution tabel to get the value of ?(1.304)

**RoRo**:

--- Quote from: Mr. MUST on April 11, 2011, 06:52:08 pm ---(i)
P(0 buses) = (1-0.16)11
P(1 bus) = 11C1(0.16)(1-0.16)10
P(2 buses) = 11C2(0.16)2(1-0.16)9

where X is number of buses passed

so

P(X<3)= P(0 Busus)+P(1 Buses)+P(2 buses)

(ii)

USE normal distribution


mean = np
        = 125(1-(0.16+0.2))
        = 125 (0.64)
       = 80
variance = npq
            = 125 (0.64)(1-0.64)
             = 28.8
let X be number of car passed

so

p(X>73)
= 1-P(X<=73)
=1 - ?((73-80)/root(28.8)
=1-?(-1.304)
=1-(1-?(1.304))
=1-1+?(1.304)
= ?(1.304)

use normal distribution tabel to get the value of ?(1.304)

--- End quote ---

I think you just solved a wrong question?
My question was about histograms.

Here' the link to the paper:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20June/6683%20June%202009.pdf

I want Question 3 please! :)

& if you don't mind can you please explain to me Question 3e of January 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20Jan/S1%202009-01.pdf

Thank you! :)

Aadeez || Zafar:
ohhh!
ur edexcel studemt srry i thought u r a cie student

Aadeez || Zafar:

--- Quote from: The Secret on April 11, 2011, 07:28:14 pm ---I think you just solved a wrong question?
My question was about histograms.

Here' the link to the paper:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20June/6683%20June%202009.pdf

I want Question 3 please! :)

& if you don't mind can you please explain to me Question 3e of January 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20Jan/S1%202009-01.pdf

Thank you! :)

--- End quote ---
widht would be::

  3*2/6 = 1 cm
and height is :

10*9/15 = 6
so 6/1 = 6 cm

SIMPLE

Aadeez || Zafar:

--- Quote from: The Secret on April 11, 2011, 07:28:14 pm ---I think you just solved a wrong question?
My question was about histograms.

Here' the link to the paper:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20June/6683%20June%202009.pdf

I want Question 3 please! :)

& if you don't mind can you please explain to me Question 3e of January 2009 on this link:
http://www.xtremepapers.net/Edexcel/Advanced%20Level/Mathematics/2009%20Jan/S1%202009-01.pdf

Thank you! :)

--- End quote ---

Var(X) = Sigma(xi2pi)-(mmean)2
= = Sigma(xi2pi)-(xipi)2
=[02(0.4)+12(0.3)+22(0.2)+32(0.1)]-[(0(0.4)+(1(0.3)+(2(0.2)+(3(0.1)/4]2
=[0(0.4)+1(0.3)+4(0.2)+9(0.1)]-[(0+0.3+0.4+0.3)]2
=[0+0.3+0.8+0.9]-(1)2
=2-1
=1

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