All Mechanics DOUBTS HERE!!!

[Saladin]

The co-ordinates have to be the same in order for something to be due south of something.

Thus, we have to see, how long it takes for the co-ordinates to become equal.

Thus, we got that the speed is

So, the co-ordinate of A is .

Thus,



The total time to get to the point is 7 seconds, .

Thus you simply add the new value to . And you get the answer:

[perrychan527]

The co-ordinates have to be the same in order for something to be due south of something.

Thus, we have to see, how long it takes for the co-ordinates to become equal.

Thus, we got that the speed is

So, the co-ordinate of A is .

Thus,



The total time to get to the point is 7 seconds, .

Thus you simply add the new value to . And you get the answer:

Thx, i got it.

[raimunts]

What is the value of acceleration due to gravity, g in m1?
And do we have to write answeres which involve g in terms of g, or in decimals? please help

[astarmathsandphysics]

9.81 or 9.8 or 10 if I am asked to find a numerrical value
I always use 9.8 but you may be told to use a value in the question
In terms of g is always best

[7ooD]

in m1 it is always 9.8

[zabady]

plzzz someone question 6 a b c for they said R is parallel to vector (i-2j) i understand by parallel that it means R=K * (i-2j).....,and for b and c i cant get them

[astarmathsandphysics]

6abc what year and board

[Saladin]

plzzz someone question 6 a b c for they said R is parallel to vector (i-2j) i understand by parallel that it means R=K * (i-2j).....,and for b and c i cant get them

which year?

[zabady]

looool sry 2009 january....m1 edexcel the linkk for paper http://freeexampapers.com/FreeExamPapers.com_.php?__lo=QSBMZXZlbC9NYXRocy9FZGV4Y2VsL00xL00xIDIwMDktMDEucGRm and the ms http://freeexampapers.com/FreeExamPapers.com_.php?__lo=QSBMZXZlbC9NYXRocy9FZGV4Y2VsL00xL00xIDIwMDktMDEgTVMucGRm

question says

6. Two forces, (4i – 5j) N and (pi + qj) N, act on a particle P of mass m kg. The resultant
of the two forces is R. Given that R acts in a direction which is parallel to the
vector (i – 2j),
(a) find the angle between R and the vector j,
(3)
(b) show that 2p + q + 3 = 0.

ms says

tan? = 2
1
?? = 63.4
angle is 153.4


(4 + p)i + (q ? 5)j
(q ? 5) = ?2(4 + p)
2 p + q + 3 = 0 *

[Saladin]

looool sry 2009 january....m1 edexcel

sir, i need to go to sleep. I have been helping all day.....

Pls take this one.

[astarmathsandphysics]

will do

[zabady]

thanks and please explain how you did part a i don't understand why they took i-2j when it is supposed to be parallel not equal

[astarmathsandphysics]

Two forces, (4i – 5j) N and (pi + qj) N, act on a particle P of mass m kg. The resultant
of the two forces is R. Given that R acts in a direction which is parallel to the
vector (i – 2j),
(a) find the angle between R and the vector j,
(3)
(b) show that 2p + q + 3 = 0.
a)cos x=j.(i-2j)/|i||i-2j|=1aqrt(5) so x=cos^-1 1/sqrt5

4i-5j+pi+qj=k(i-2j)
4+p=k   (3)
-5+q=-2k (4)
(3)*2+(4) gives2p + q + 3 = 0

[raimunts]

Hey, can someone please suggest 2 or 3 of the MOST DIFFICULT solomon paper questions of each chapter of M1? Please help!

[zabady]

i dnt get part a at all