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Author Topic: C1 and C2 DOUBTS HERE!!!!!  (Read 97509 times)

Offline Blizz_rb93

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Re: C1 DOUBTS HERE!!!!!
« Reply #60 on: May 15, 2010, 06:42:32 pm »
What's the equation to finding the length of a line ??
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Offline astarmathsandphysics

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Re: C1 DOUBTS HERE!!!!!
« Reply #61 on: May 15, 2010, 06:50:56 pm »
distance between 2 points sqrt((x_2 -x_1)^2 +(y_2 -y_1)^2)
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Offline wakemeup

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Re: C1 DOUBTS HERE!!!!!
« Reply #62 on: May 15, 2010, 07:05:26 pm »
Quote from: vanibharutham on May 14, 2010, 05:52:14 pm
10a)

hmm

easy way to do this:

you know that the curve will cross the x-axis when y = 0
therefore, x = -3 and x = 1

You should also note that it is a cubic function

and that when x = 0 , y = 3

you know have three points

(0,3) (-3,0) and (1,0)

make sure it goes through those points and that it is cubic

here is a sketch:
http://www.wolframalpha.com/input/?i=plot+x%C2%B3+%2B+x%C2%B2+-5x+%2B+3


Ok, I got 7(d) but how exactly do you know whether the curve in 10(a) goes up then down or down then up.
« Last Edit: May 15, 2010, 07:16:20 pm by wakemeup »
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Offline astarmathsandphysics

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Re: C1 DOUBTS HERE!!!!!
« Reply #63 on: May 15, 2010, 07:16:20 pm »
For cubics if it is x^3 not -x^3 graph will be like in the link
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Offline halosh92

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Re: C1 DOUBTS HERE!!!!!
« Reply #64 on: May 20, 2010, 02:18:51 pm »
Q2
thx :)
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Offline Saladin

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Re: C1 DOUBTS HERE!!!!!
« Reply #65 on: May 20, 2010, 06:43:18 pm »
Quote from: halosh92 on May 20, 2010, 02:18:51 pm
Q2
thx :)

\sum_{0}^{30}(7+2r)-\sum_{0}^{9}(7+2r)

1147-160

987

I am sure you can figure it out now.
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Offline halosh92

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Re: C1 DOUBTS HERE!!!!!
« Reply #66 on: May 20, 2010, 06:52:09 pm »
Quote from: Engraved on May 20, 2010, 06:43:18 pm
\sum_{0}^{30}(7+2r)-\sum_{0}^{9}(7+2r)

1147-160

987

I am sure you can figure it out now.

there is my doubt exactly  ;D
why did u subtract "9" from 30 ???
thx alot ;)
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everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline Saladin

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Re: C1 DOUBTS HERE!!!!!
« Reply #67 on: May 20, 2010, 06:53:54 pm »
Quote from: halosh92 on May 20, 2010, 06:52:09 pm
there is my doubt exactly  ;D
why did u subtract "9" from 30 ???
thx alot ;)

It is the sum of terms 10 to 30. Inclusive of the 10th term.

Thus, you have to subtract the sum of the first 9 terms to get the answer.

I hope that answers your question.
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Offline halosh92

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Re: C1 DOUBTS HERE!!!!!
« Reply #68 on: May 20, 2010, 07:17:31 pm »
Quote from: Engraved on May 20, 2010, 06:53:54 pm
It is the sum of terms 10 to 30. Inclusive of the 10th term.

Thus, you have to subtract the sum of the first 9 terms to get the answer.

I hope that answers your question.

so we always exclude!
thx a bunch! ;)
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everyday we wake up is a miracle, then how do we say miracles dont happen?????

Offline Blizz_rb93

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Re: C1 DOUBTS HERE!!!!!
« Reply #69 on: May 22, 2010, 09:13:28 pm »
Can someone please help me with January 2010 Question 4 and Question 6

Thank you.
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Offline astarmathsandphysics

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Re: C1 DOUBTS HERE!!!!!
« Reply #70 on: May 22, 2010, 10:22:10 pm »
jan 2010 q4 and 6
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Offline Blizz_rb93

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Re: C1 DOUBTS HERE!!!!!
« Reply #71 on: May 22, 2010, 10:41:12 pm »
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Offline 7ooD

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Re: C1 DOUBTS HERE!!!!!
« Reply #72 on: May 23, 2010, 01:17:19 am »
@ wakemeup look dude to find it find first where does the graph hit the x axis which are -3 and 1 but here 1 is repeated twice as it is (x-1)^2 so whenever u find square wat u do make the graph touch at that value dnt cross like others and to kno whether the graph start from up or down check if the x is positive then start from up as the graph we have in 10 a but if negative start from down
« Last Edit: May 23, 2010, 01:19:52 am by 7ood »
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Offline zabady

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Re: C1 DOUBTS HERE!!!!!
« Reply #73 on: May 23, 2010, 01:21:10 am »
i have a doubt at jan 2008 6 c
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Offline Saladin

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Re: C1 DOUBTS HERE!!!!!
« Reply #74 on: May 23, 2010, 05:54:41 am »
Quote from: zabady on May 23, 2010, 01:21:10 am
i have a doubt at jan 2008 6 c

a=2

Because what you have to do is simple give a function, that will map the current graph to have the maximum point in the y-axis.

This means moving the graph 2 units horizontally to the rite.

Thus, the graph is y=f(x+2)
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