ok heres the (c) (ii) part
the formula i used = Object matrix * Transformation matrix = Image Matrix
The object matrix can contain 3 sets of values as the object is a triangle, however , as it is difficult to work with a 3*3 matrix, we'll go for only two sets of values from the triangle. TAke any two sets of vertices
I chose : A : (8,6)
B : (6,10)
Now the image matrix will be A| : (6,8)
B| : (10,6)
Arrange this in a form of matrix (formula), note : the set of values is arranged vertically (column wise)
(8 6) * Transformation Matrix = (6 10)
(6 10) (8 6)
Now by simple algebra we'll get --> Transformation Matrix = (6 10) * (8 6 )-1
(8 6) (6 10)
The inverse of (8 6 ) is (10/44 -6/44)
(6 10) (-6/44 8/44)
Therefore Transformation Matrix = (6 10) * (10/44 -6/44) = (0 1)
(8 6) (-6/44 8/44) (1 0)
Thus the Transformation Matrix = (0 1)
(1 0)
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nest up, e part
