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astarmathsandphysics:
which paper

ruby92:
m/j 2002 paper 1

ruby92:
M/j 2004 paper 1
8 (why D why not C)
9
31(why D and why not C)

O/N 2004 paper 1
20, 18,11,31,33,26.

astarmathsandphysics:
can you post question and paper and year in same post
mj 2004 p1 q8 D - as ball speeds up acc falls as air resistance increases]

9. Work vertically s=ut+1/2at^2 u=0 cos he vertically speed is zero
1.25=0+1/2*10*t^2
t=0.5
work horizontally s=ut 10=u*0.5 u=20
31. R=pl/A and A=kd^2 so double the diameter mean divide resistance by 4. V=IR and V is same for wires in parallel so current in P is 4x cuurent in Q

astarmathsandphysics:
20. A cos P=pgh
so 2xp(P)+xp(Q)=2xp(Q) so xp(P)=2p(Q) so p(P)1/2p(Q)
18.work dine=increase in potential energy+heat generated
9000*40=20000*12+H
H=120000J A
11.B m(v-u)=m(-v-v)=-2mv
31. C use P=VI
33.R=pl/A double the length means double R and double the diameter means 1/4 R so R is halved overall
V=IR so double V and hal;ve R mean I is 4x bigger
26 !6 I=kA^2

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