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ruby92:
O/n 2003 paper 2 CIE physics
Q3 (C) part iii 2. how is the torque of this also 45?

Q5 of the same papers part c

m/j 2004 paper 2
1 (b)

ruby92:
Posted by: astarmathsandphysics
can you post question and paper and year in same post
mj 2004 p1 q8 D - as ball speeds up acc falls as air resistance increases]

9. Work vertically s=ut+1/2at^2 u=0 cos he vertically speed is zero
1.25=0+1/2*10*t^2
t=0.5
work horizontally s=ut 10=u*0.5 u=20
31. R=pl/A and A=kd^2 so double the diameter mean divide resistance by 4. V=IR and V is same for wires in parallel so current in P is 4x cuurent in Q

i dont get 31  ??? ???

ruby92:
M/j 2004 paper 2 physics
5 b
3 B ii
1 b

o/n 2004 paper 2
1 b ii

m/j 2005
3 b we dont convert g to kg?

astarmathsandphysics:
3bii)s=1/2at^2 a=s/(1/2t^2)=2*gradient of graph=
on2004p2 %error =2*0.02/0.50*100=8%
mj2005 you should convert to kg it is good practice but units of grams cancels cos factor of 1000 occurs on both sides

ruby92:
O/n 2005 paper 2
3 c

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