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ruby92:
M/j 2003 paper1
34,40,18,30,35

ruby92:
o/n 2003 paper 1
12,7(why isnt it A how is it B?arent we supposed to find the gradient?)and 37,16

astarmathsandphysics:
34.0 to 7,5 cos 0 to 5/6 of resistaNCE can be between P and Q
30.D since 2*2/3 -1/3 =1 charges must add up to 1
18.D since KE is propritional to v^2 F=Energy =braking force*distance=1/2mv^2
30.average current =(100+20)/2=60mA
charge=It=60mA*8=480mC
45. E is uniform between paralell plates

astarmathsandphysics:
7 C horizontal acceleration is 0 so horizontal vel is constant=ucos alpha
apply v=u+at vertically
12. 8*2+2*4=6v v=4

ruby92:

--- Quote from: ruby92 on April 26, 2010, 05:20:05 pm ---2.why not A? how do we know the direction of the resultant force?
could you please explain Q's 15 and 35 in more detail

Also o/n 2002 paper 1; 36

--- End quote ---

no 12(o/n 2003)  ??? ???

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