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Author Topic: All doubts here!  (Read 56087 times)

Offline wassup

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Re: ANY HELP!
« Reply #15 on: October 22, 2009, 07:28:36 pm »
Quote from: The Dude 321 on October 22, 2009, 07:25:03 pm
If anyone needs any help, pls tell me, i have just a little but more time, please tell me uf u need help with any of the subjects...

can u explain me d concept of oxidation no. and nd parallelogram law (by sin, cos).
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Offline Saladin

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Re: ANY HELP!
« Reply #16 on: October 22, 2009, 07:32:38 pm »
Oxidation is the loss of elections and the gain of oxygen. The oxidation number is the same as the valence number, basically the value of the charge that an ion of the element has. Thats really it. Now, if the oxidation number is negative, then it can still lose electrons, thus it can reduce other elements or atoms, thus they are called reducing agents. About the paralellogram law, u dont need to know that for the IG using sin and cos...
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Offline Ghost Of Highbury

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Re: ANY HELP!
« Reply #17 on: October 22, 2009, 07:34:24 pm »
Quote from: wassup on October 22, 2009, 07:28:36 pm
can u explain me d concept of oxidation no. and nd parallelogram law (by sin, cos).

for the oxidation thingy

check this- a sample solved question (all details mentioned)

https://studentforums.biz/index.php/topic,3773.msg112331/topicseen.html#msg112331

for the parallelogram thingy - i advise u to use the scale (1cm = 10N) method to solve it instead of using trigonometry.

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Offline wassup

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Re: ANY HELP!
« Reply #18 on: October 22, 2009, 07:35:04 pm »
Quote from: The Dude 321 on October 22, 2009, 07:32:38 pm
Oxidation is the loss of elections and the gain of oxygen. The oxidation number is the same as the valence number, basically the value of the charge that an ion of the element has. Thats really it. Now, if the oxidation number is negative, then it can still lose electrons, thus it can reduce other elements or atoms, thus they are called reducing agents. About the paralellogram law, u dont need to know that for the IG using sin and cos...

Can u plz looak at q1 from physics o level paper 2 oct/nov 08 n temme how to do it.
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Offline Saladin

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Re: ANY HELP!
« Reply #19 on: October 22, 2009, 07:36:17 pm »
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Offline Saladin

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Re: ANY HELP!
« Reply #20 on: October 22, 2009, 07:36:54 pm »
please upload the file.
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Offline wassup

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Re: ANY HELP!
« Reply #21 on: October 22, 2009, 07:38:49 pm »
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Offline Ghost Of Highbury

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Re: ANY HELP!
« Reply #22 on: October 22, 2009, 07:45:04 pm »
Quote from: wassup on October 22, 2009, 07:35:04 pm
Can u plz looak at q1 from physics o level paper 2 oct/nov 08 n temme how to do it.
refer to the diagram

use the scale of 1cm = 1N to draw the diagram accurately..


next, draw the rectangle

the diagonal of the rectangle = the resultant force

find this by measuring it with ur ruler and using the scale to find the exact value

it shud be 10cm = 10N

u can also calculate the diagonal using the pythagoras theorm = sqrt(82 + 62) = sqrt (100) = 10

to find the direction find the angle from line M in the diagram
it shud be around 55 degree...
« Last Edit: October 22, 2009, 07:47:09 pm by | am | »
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Offline Saladin

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Re: ANY HELP!
« Reply #23 on: October 22, 2009, 07:49:56 pm »
ya thats the right way.....

u dont even hav to make it a paralellogram...
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Offline Ghost Of Highbury

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Re: ANY HELP!
« Reply #24 on: October 22, 2009, 07:50:41 pm »
Quote from: The Dude 321 on October 22, 2009, 07:49:56 pm
ya thats the right way.....

u dont even hav to make it a paralellogram...

yeah..gave him both the options..
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Offline wassup

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Re: ANY HELP!
« Reply #25 on: October 22, 2009, 07:53:17 pm »
Quote from: | am | on October 22, 2009, 07:45:04 pm
refer to the diagram

use the scale of 1cm = 1N to draw the diagram accurately..


next, draw the rectangle

the diagonal of the rectangle = the resultant force

find this by measuring it with ur ruler and using the scale to find the exact value

it shud be 10cm = 10N

u can also calculate the diagonal using the pythagoras theorm = sqrt(82 + 62) = sqrt (100) = 10

to find the direction find the angle from line M in the diagram
it shud be around 55 degree...

thank u very much
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Offline Ghost Of Highbury

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Re: ANY HELP!
« Reply #26 on: October 22, 2009, 07:53:51 pm »
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Offline Saladin

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Re: ANY HELP!
« Reply #27 on: October 22, 2009, 07:54:31 pm »
Anything else, srry i cud not answer in time, my int is slow.
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Offline wassup

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Re: ANY HELP!
« Reply #28 on: October 22, 2009, 08:05:10 pm »
Quote from: The Dude 321 on October 22, 2009, 07:54:31 pm
Anything else, srry i cud not answer in time, my int is slow.

no problem and thanks fr giving me ur valuable time.
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Offline Saladin

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Re: ANY HELP!
« Reply #29 on: October 22, 2009, 08:08:13 pm »
np.

anyone need anything else, got 20 more mins and counting.
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