Additional Math Help HERE ONLY...!

[BlackBunny103]

OH, & for variant 2, the combination question for choosing 7 pieces from 6 classical & 4 modern pieces..
i got 10C7 = 120ways for i) and 100 ways for ii) did anyone get the same answers?

Yes yes, same same with me

[jellybeans]

Yes yes, same same with me

HAHA , (Y) whabbout Q12? which one didyou choose? i chose the bottom oneee.. and the coordinates for when the tangent meets the x axis is like.. (0.231, 0) ?

[jellybeans]

Yup I recalled the question, I am guessing that P2 is going to be easy as all the hard topics were featured in yesterday's paper ...

By the way what did you got for OC ?

for the OC thing there was a double 'minus' sign when you added OA & AC right? so it makes it all positive.. or something hahahahaa

[tunnellord]

ADD Math was real good. Im expecting full!

[$KD1994$]

HAHA , (Y) whabbout Q12? which one didyou choose? i chose the bottom oneee.. and the coordinates for when the tangent meets the x axis is like.. (0.231, 0) ?

i gt d same answer.!!.....!!

[jellybeans]

i gt d same answer.!!.....!!

HAHAHA yaay! do you think P2's gonna be okayy? hahaha , i hope its not too hard

[Dibss]

Hmm, can someone who did variant 1 tell us what came out in their paper 1?

Variant one was possibly the easiest AddMath P1 I have ever given... Aced it for sure
Which means P2's gonna be hard

@Aangel42 - My grade uses Additional Mathematics 6th Edition by JF Talbert and HH HENG

[Ghost Of Highbury]

What textbook do you guys use to study for Additional Math?

Are there any resources online I could use to study for it?

Buy redspot publications books for gce-o level additional maths (= IGCSE)

[xlane]

p1 1zt variant..4 b..any1 rememberz da answerz 4 ..xny..xuy..nd (xuy)'nz..

[Ghost Of Highbury]

Thanks ghost o highbury..bt u r hardly a ghost..u can type n ur usin a modern technology

LOL, call me Aadi

[BlackBunny103]

Hey guys, would you please help me with this question? It's from MJ 2007 P2.
Thanxx

[adrian1993]

Blackbunny, I presume that you have to equate both equations?

Then use b square-4ac=>0.


I need help on May June 2003 Paper 2 Question 5 Part iii.

How do I get the domain and range of the inverse? I don't quite understand. Urgent help needed.

[Ghost Of Highbury]

Hey guys, would you please help me with this question? It's from MJ 2007 P2.
Thanxx

y = (x² + 4)/2

y= 3x - k

(x² + 4 ) /2 = 3x- k
(
k = -0.5x² + 3x - 2

 -0.5x² + 3x - 2 -k = 0

multiply both sides with -2

x^2 - 6x + (4+2k) = 0

now to intersect at a point, use b^2 - 4ac >= 0

36x^2 - 16x^2 - 8kx^2 >= 0

simplify

k =< 2.5

[Ghost Of Highbury]

Blackbunny, I presume that you have to equate both equations?

Then use b square-4ac=>0.


I need help on May June 2003 Paper 2 Question 5 Part iii.

How do I get the domain and range of the inverse? I don't quite understand. Urgent help needed.

The domain of f(x) is the range of f^-1 (x)

The range of f(x) is the domain of f^-1(x)

So the range of f^-1(x) --> x >= 0 (domain of f(x)

and the domain of f^-1(x) ---> x >= 0.5 (range of f(x)

range of f(X) = the least value of f(x) is when x = 0

when x = 0, f(x) = 0.5

so as x>=0 , f(x) >=0.5

[elemis]

This stuff looks WAAAAAAY harder than my normal math.