sum1 explain how to solve da 2nd n 3rd part of oct/nov 2002 p1..12 either..please
ii) when theta = 30
R = r(1+1/sin 30) = 3r
Area of circle = pi*r^2
Area of sector = 1/2 R^2(pi/3) = (3pir^2)/2
fraction : pir^2/(3pir^2)/2 = 2/3
iii) tan 30 = r/d (R = 15 , 15 = 3r , r = 5)
tan 30 = 5/d
d = 5/tan 30 = 8.66
arc length = r*a = 5(2pi/3) = 10.47
perimeter = 10.47 + 2(8.66) = 27.8