Solving the attachment.(5) (i)OA = OB
(AB)
2 = (OA)
2 + (OB)
2(AB)
2 = (6)
2 + (6)
2(AB)
2 = 36 + 36
(AB)
2 = 72
AB = 

AB = OD
angle BAD : tan 

 = 
)
tan 

 =  6/6

 = tan-1 (6/6)

 = 45
o or 
\pi)
 = 
\pi)
length of arc :
 s = 
r X 
                                = 

 X 
\pi)
                                = 6.664324407 or 6.67 (correct to 3 significant figures)
(ii)Area of shaded region = Area of sector ABD - Area of triangle AOB
Area of shaded region = [ r^2) X
 X  ] - [
 ] - [ ) X b X h] ]
 X b X h] ]Area of shaded region = [ 
)
 X 72 X 
)
 ] - [ 
)
 X 6 X 6]
Area of shaded region = 9

 - 18
Area of shaded region = 9 (

 - 2) = 10.2743338 or 10.3 (correct to 3 significant figures)