Solving the attachment.(5) (i)OA = OB
(AB)
2 = (OA)
2 + (OB)
2(AB)
2 = (6)
2 + (6)
2(AB)
2 = 36 + 36
(AB)
2 = 72
AB =
AB = OD
angle BAD : tan
=
tan
= 6/6
= tan-1 (6/6)
= 45
o or
=
length of arc :
s =
r X =
X
= 6.664324407 or 6.67 (correct to 3 significant figures)
(ii)Area of shaded region = Area of sector ABD - Area of triangle AOB
Area of shaded region = [ X ] - [ X b X h] ]Area of shaded region = [
X 72 X
] - [
X 6 X 6]
Area of shaded region = 9
- 18
Area of shaded region = 9 (
- 2) = 10.2743338 or 10.3 (correct to 3 significant figures)