Solving the attachment.(5) (i)OA = OB
(AB)
2 = (OA)
2 + (OB)
2(AB)
2 = (6)
2 + (6)
2(AB)
2 = 36 + 36
(AB)
2 = 72
AB =

AB = OD
angle BAD : tan

=
)
tan

= 6/6

= tan-1 (6/6)

= 45
o or
\pi)
=
\pi)
length of arc :
s =
r X 
=

X
\pi)
= 6.664324407 or 6.67 (correct to 3 significant figures)
(ii)Area of shaded region = Area of sector ABD - Area of triangle AOB
Area of shaded region = [
X
] - [
X b X h] ]Area of shaded region = [
)
X 72 X
)
] - [
)
X 6 X 6]
Area of shaded region = 9

- 18
Area of shaded region = 9 (

- 2) = 10.2743338 or 10.3 (correct to 3 significant figures)