« previous next »
Pages: [1] 2   Go Down

Author Topic: PP2 Math question  (Read 3879 times)

Offline yasser37

  • SF Citizen
  • ***
  • Posts: 228
  • Reputation: 2832
PP2 Math question
« on: May 12, 2009, 11:36:17 am »
Hey all


I am doing the pp

I faced one hard q till now

its

O/N 06 Q 21 B

Logged

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: PP2 Math question
« Reply #1 on: May 12, 2009, 12:02:52 pm »
If you want me to answer can you post the question but not the paper as i am on a mobile phone
Logged

Offline yasser37

  • SF Citizen
  • ***
  • Posts: 228
  • Reputation: 2832
Re: PP2 Math question
« Reply #2 on: May 12, 2009, 01:28:16 pm »
There is a drawing

I can't post
Logged

Offline yasser37

  • SF Citizen
  • ***
  • Posts: 228
  • Reputation: 2832
Re: PP2 Math question
« Reply #3 on: May 12, 2009, 02:12:16 pm »
any1?
Logged

Offline theigstudent

  • SF Senior Citizen
  • *****
  • Posts: 658
  • Reputation: 277
  • Gender: Female
Re: PP2 Math question
« Reply #4 on: May 12, 2009, 02:39:21 pm »
even i m stuck on same ques
some one plzzzzz help
Logged
<3 datz da way it izzzzzzzzzz <3

Offline astarmathsandphysics

  • SF Overlord
  • *********
  • Posts: 11271
  • Reputation: 65534
  • Gender: Male
  • Free the exam papers!
Re: PP2 Math question
« Reply #5 on: May 12, 2009, 02:51:26 pm »
Half hour
Logged

Offline angell

  • SF Senior Citizen
  • *****
  • Posts: 866
  • Reputation: 159
  • Gender: Female
  • -cuz it aint ever good enuf to be true!
Re: PP2 Math question
« Reply #6 on: May 12, 2009, 03:13:53 pm »
Q21
Its about finding the equation of  a straight line which is always y=mx+c
First find the gradient
Using 1,-2 and 4,3
y2-y1/ x2-x1
m= 3-(-2)/4-1
m =3+2/3
m=5/3

Then, substitue m=5/3 in the equation y=mx+c

y=mx+c (using 1,-2)
-2 = 5/3 X 1 + c
-2 = 5/3 + c
c = 11/3

Then, substitute m and c in y = mx+c
so the equation of the line is y=5/3x + 11/3

(By the way i hope this is the question you were after:P)
Logged
oh churiyaan charha dey..
oh mehndiya kara dey..
oh jhanjara pawan dey...
On the dance floor oh mundiye...Nach Baliye!

--~*O yaara dhol bajaake.. O yaara jashan mana ke!!




-----------------------------------------

Offline yasser37

  • SF Citizen
  • ***
  • Posts: 228
  • Reputation: 2832
Re: PP2 Math question
« Reply #7 on: May 12, 2009, 03:45:03 pm »
One more quetion please

it's

June 02 Page 6 Q 12

and thanks angell   for answering
« Last Edit: May 12, 2009, 03:46:56 pm by yasser37 »
Logged

Offline yasser37

  • SF Citizen
  • ***
  • Posts: 228
  • Reputation: 2832
Re: PP2 Math question
« Reply #8 on: May 12, 2009, 06:03:56 pm »
It is actually question 13
Logged

Offline zubair_slipknot

  • SF Citizen
  • ***
  • Posts: 140
  • Reputation: 5
  • Gender: Male
  • A new A* starer has been born in the world of IG
Re: PP2 Math question
« Reply #9 on: May 12, 2009, 07:16:36 pm »
hi i am having a problem in maths may june paper 2 2007

q. 12 pg.11

part (b)

South Wesern Bank advertises savings with compund intrest at 4.9% per year. Kalid brother invests his money in this baml.At the end of 3 years, how much more money will he have than Kalid?

its urgent actually as i do not have much time for my next exam of maths...thx
Logged
the only way to pass in IGCSE is to be determinant and should have a good self esteem...thts the best description i can get from my mind!!!!

Offline anshasi

  • Newbie
  • *
  • Posts: 29
  • Reputation: 7
Re: PP2 Math question
« Reply #10 on: May 12, 2009, 07:47:30 pm »
THIS IS THE ANSWER FOR JUN 2006 q13
CROSS  MULTIPLICATION U GET 3(X-2)=4(2X+5)
3X-6=8X+20
3X=8X+26
-5X=26
-X=5.2
X=-5.2
 ;D
Logged

Offline anshasi

  • Newbie
  • *
  • Posts: 29
  • Reputation: 7
Re: PP2 Math question
« Reply #11 on: May 12, 2009, 08:01:57 pm »
ZUBAIR_M U MEAN QUESTION 22 )b)
A)2000*3*(5/100)=300
300+2000=2300

B)2000(1+(4.9/100))^3                                  ^ IS TO THE POWER OF
2000(1.049)^3
=2368.6
2368.6-2300=8.6
 ;)
Logged

Offline theigstudent

  • SF Senior Citizen
  • *****
  • Posts: 658
  • Reputation: 277
  • Gender: Female
Re: PP2 Math question
« Reply #12 on: May 12, 2009, 08:05:36 pm »
Quote from: zubair_m on May 12, 2009, 07:16:36 pm
hi i am having a problem in maths may june paper 2 2007

q. 12 pg.11

part (b)

South Wesern Bank advertises savings with compund intrest at 4.9% per year. Kalid brother invests his money in this baml.At the end of 3 years, how much more money will he have than Kalid?

its urgent actually as i do not have much time for my next exam of maths...thx


use compound interest formula

A= P(1+R/100)n

 = 2000(1+4.9/100)3
 =2308.64
             2308.64-2300= 8.64
Logged
<3 datz da way it izzzzzzzzzz <3

Offline angell

  • SF Senior Citizen
  • *****
  • Posts: 866
  • Reputation: 159
  • Gender: Female
  • -cuz it aint ever good enuf to be true!
Re: PP2 Math question
« Reply #13 on: May 12, 2009, 08:50:05 pm »
huh im suckin at math so much rite now....nyways guys could someone tell me how to solve Q.5, Q.7  Oct/Nov 2008 P2...

IN Q.7 could somebody tell me the bounds im supposed to take?? im taking 6.15 and 8.15 but not gettin the answer according to the mark scheme??
« Last Edit: May 12, 2009, 08:53:46 pm by angell »
Logged
oh churiyaan charha dey..
oh mehndiya kara dey..
oh jhanjara pawan dey...
On the dance floor oh mundiye...Nach Baliye!

--~*O yaara dhol bajaake.. O yaara jashan mana ke!!




-----------------------------------------

Offline anshasi

  • Newbie
  • *
  • Posts: 29
  • Reputation: 7
Re: PP2 Math question
« Reply #14 on: May 12, 2009, 09:28:44 pm »
ACTUALLY I MADE A TYPING MISTAKENUMBER IS 2308.6 NOT 2368.6 :(
ZUBAIR_M U MEAN QUESTION 22 )b)
A)2000*3*(5/100)=300
300+2000=2300

B)2000(1+(4.9/100))3                                  
2000(1.049)3
=2308.6
2308.6-2300=8.6
Logged
Pages: [1] 2   Go Up
« previous next »