[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

[Aadeez || Zafar]

MJ 2004 Q10 part one,i was always wondering why do you have to change the sign of the least value,anyone knows that?

give me the link of the question paper

[elemis]

MJ 2004 Q10 part one,i was always wondering why do you have to change the sign of the least value,anyone knows that?

x² -2x >15

Hence,  x² -2x -15 > 0

Solving this gives the two critical values :

x = -3 and x = 5

Sketching a parabola with these values (see below).

Since the inequality states that x must be GREATER than zero we are only interested in x-coordinates that meet the red part of the parabola.

Hence, x<-3 , x>5

[thecandydoll]

7With respect to the origin O, the points A and B have position vectors given by OA = i + 2j + 2k and
 OB = 3i + 4j. The point P lies on the line AB and OP is perpendicular to AB.
(i) Find a vector equation for the line AB.   [1]
(ii) Find the position vector of P.   [4]
(iii) Find the equation of the plane which contains AB and which is perpendicular to the plane OAB, giving your answer in the form ax + by + c? = d.

i dont get the second part

[HUSH1994]

Thanks man you really fit for a teacher

[Chingoo]

Could someone solve P31 May June 10 Q1 GRAPHICALLY? Thanks on advance to whoever does me the great favor!

[EMO123]

you may think that am i gone crazzy or what but
can you tell me is 2 a prime number or not
and is 1 a prime number

it is very simple to say this to me so any one faster as much as you can

[HUSH1994]

yeah 1 & 2 are prime numbers

[EMO123]

yeah 1 & 2 are prime numbers

thanx friend but i am just stupid for a while
but now it's clear thanx friend

[HUSH1994]

anytime

[EMO123]

paper 1
8709/1/o/n/01
Question No. 3

[elemis]

paper 1
8709/1/o/n/01
Question No. 3

The inverse function of y=cosx is     x = cos^-1y

x = cos^-1y has a range of 0 to pi.

Since the range of the inverse function is the domain of the normal function :

k = pi

[EMO123]

The inverse function of y=cosx is     x = cos^-1y

x = cos^-1y has a range of 0 to pi.

Since the range of the inverse function is the domain of the normal function :

k = pi

thanxx ari

[m.bhaiyat]

hey guys..need help on may june 2009 questions 1,3(ii), and 4.
thanks

[astarmathsandphysics]

hey guys..need help on may june 2009 questions 1,3(ii), and 4.

 see attachment

[SkyPilotage]

I rlly dont know how to explain math on computer...
On question number 1, its always better to make 2 fraactions into a single fraction. Here you will have in the denominator (1+sinx)(1-sinx)=(1-sin^2x)=cos^2x
and the numerator would be sinx(1+sinx)-sinx(1-sinx)=sinx+sin^2x-sinx+sin^2x=2sin^x
There you go 2tan^x.
Question 3 ii)
you will multiplay ax by the "x" in the other brackets and multiplay 1 by the x^2 term in the other brackets. Their sum must be equal to zero!
Question 4 i)
-substitue x=0 y=3 ---->c=3
-ok now the maximum value for any sin function is 1 and minimum is -1. same thing for cosine.
so when y=9 sinbx=1 so a=6
-hmm now when u have sin(2x) the x values of sinx are divided by 2. so its as if its compressed by two. Look at the graphs of sin2x and sinx and compare. Maybe someone could have a better explanation for this last part.