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Author Topic: ALL CIE PHYSICS DOUBTS HERE !!!  (Read 171667 times)

Offline Sue T

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #600 on: May 10, 2011, 04:39:34 pm »
Quote from: TJ-56 on May 10, 2011, 02:58:00 pm
May June 2005 Q6 (b) Posted, again i just want to make sure its the correct answer
thanx
yes -  the differential of sine is cosine so yes
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Offline TJ-56

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #601 on: May 10, 2011, 04:48:46 pm »
Quote from: Sue T on May 10, 2011, 04:39:34 pm
yes -  the differential of sine is cosine so yes
ur awesome, thanx again!
+rep
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Offline TJ-56

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #602 on: May 10, 2011, 04:49:28 pm »
May June 2006 2 (b) (ii) The volume in the ‘baloon’ conditions become 5.405 x10^6, so why cant we just divide that value be 7.24 x 10^3 and round the answer from 746.54 to 746. the answer on the ms is 741, and what is meant by:  (answer 740 or ““fails to allow for gas in cylinder””, max 2/3) ?
May June 2006 6 (a) (i) what exactly do we have to draw?  
thanx in advance
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Offline physichemaths

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #603 on: May 10, 2011, 10:26:56 pm »
how to draw the graph for november 2007 paper 4 question 10 (c)?
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Offline Sue T

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #604 on: May 11, 2011, 02:11:21 am »
Quote from: TJ-56 on May 10, 2011, 04:49:28 pm
May June 2006 2 (b) (ii) The volume in the ‘baloon’ conditions become 5.405 x10^6, so why cant we just divide that value be 7.24 x 10^3 and round the answer from 746.54 to 746. the answer on the ms is 741, and what is meant by:  (answer 740 or ““fails to allow for gas in cylinder””, max 2/3) ?
May June 2006 6 (a) (i) what exactly do we have to draw?  
thanx in advance

i codnt log in - some network errror - u might not c th answer till after the xam but - wateve:
for bii) the original cylinder's volume must be included cuz some might be left over in it and it dsnt fill any balloons - so you have 2 include that in the calculation of ur new volume-thts as far as i can help you
6ai) it is a vertical downward arrow for direction of B (think of th flux lines atound y) and an arrow to the right for th force - im talkin bout those 2 lines being xactly on point Q - 2 find the direction of th force, use flemings left hand
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Offline MistahNobodeh

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #605 on: May 11, 2011, 09:03:54 am »
Quote from: Sue T on May 11, 2011, 02:11:21 am
i codnt log in - some network errror - u might not c th answer till after the xam but - wateve:
for bii) the original cylinder's volume must be included cuz some might be left over in it and it dsnt fill any balloons - so you have 2 include that in the calculation of ur new volume-thts as far as i can help you
6ai) it is a vertical downward arrow for direction of B (think of th flux lines atound y) and an arrow to the right for th force - im talkin bout those 2 lines being xactly on point Q - 2 find the direction of th force, use flemings left hand
In the balloon question u cannot just divide the Volumes cuz they are both at different pressures and according to PV=nRT Vis directly propotional to n only and only if all other quantities are constant.
In the wire question....The arrow B should be downwards since according to the right hand grip rule that will be the component of wire XY's magnetic field onto the wire PQ. The force should be towards the right hand side(towards XY) in accordance with the Fleming's left hand rule.
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Offline NidZ- Hero

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #606 on: May 12, 2011, 08:38:36 am »
three coplanar forces, each of magnitude of 10N ACT, through the same point of a body in the direction shown


what is the magnitude of the resultant force?
A.  0N
B.  1.3N
C. 7.3 N
D. 10 N 

can yu plz show the working
tahnx   ;)
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elemis

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #607 on: May 12, 2011, 08:43:47 am »
Quote from: Nidzzz on May 12, 2011, 08:38:36 am
three coplanar forces, each of magnitude of 10N ACT, through the same point of a body in the direction shown


what is the magnitude of the resultant force?
A.  0N
B.  1.3N
C. 7.3 N
D. 10 N 

can yu plz show the working
tahnx   ;)

Can you attach the diagram or link me to the original question ?
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Offline cashem'up

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #608 on: May 12, 2011, 11:01:08 am »
Quote from: Nidzzz on May 12, 2011, 08:38:36 am
three coplanar forces, each of magnitude of 10N ACT, through the same point of a body in the direction shown


what is the magnitude of the resultant force?
A.  0N
B.  1.3N
C. 7.3 N
D. 10 N 

can yu plz show the working
tahnx   ;)

if they complete a vector triangle its zero... otherwise plz attach the diagram..
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Offline mdwael

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #609 on: May 12, 2011, 11:01:44 pm »
Please can someone solve this? Even after looking at the mark scheme I still dont get it.... I found the first part but part (ii) is still confusing.
I attached the picture of the question.

The mark scheme says exactly..

 (ii)  moment = force × perpendicular distance
    = 0.051 × 9.8 × 0.61 × sin18  
    = 0.094 N

I dont get this explanation :/

This question is from october november 2007
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Offline NidZ- Hero

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #610 on: May 13, 2011, 07:42:27 am »
describe the motion as the object dropped from a height and rebounds from the ground And its inelastic ?

can u aid the explanation with a graPh plz
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Offline NidZ- Hero

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #611 on: May 14, 2011, 05:33:02 am »
Quote from: Ari Ben Canaan on May 12, 2011, 08:43:47 am
Can you attach the diagram or link me to the original question ?
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Offline NidZ- Hero

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #612 on: May 14, 2011, 07:21:41 am »
A body, intially at rest explodes into two masses M1 And M2
that move apart with speeds v1 and v2 respectively
what is the ratio of v1/v2?

A. M1/M2
B. M2/M1
C. (M1/M2)^1/2
D. (M2/M1)^1/2

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elemis

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #613 on: May 14, 2011, 07:33:26 am »
Quote from: Nidzzz on May 12, 2011, 08:38:36 am
three coplanar forces, each of magnitude of 10N ACT, through the same point of a body in the direction shown


what is the magnitude of the resultant force?
A.  0N
B.  1.3N
C. 7.3 N
D. 10 N 

can yu plz show the working
tahnx   ;)

Resolving vertically.

10cos30 + 10cos30 - 10 = 7.32 N
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Offline EMO123

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #614 on: May 14, 2011, 07:35:30 am »
Quote from: Ari Ben Canaan on May 14, 2011, 07:33:26 am
Resolving vertically.

10cos30 + 10cos30 - 10 = 7.32 N
thanx ari
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