Author Topic: IGCSE CHEMISTRY DOUBTS  (Read 28745 times)

Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #105 on: June 04, 2010, 06:35:22 pm »
May june 08 q 8 b 3 the first one my answer was N-H & C=O bonds is it correct & if not what is ?
the second one i dnt quite get what the ms says ??

Just say:

Similarity: They both have an amide linkage.

Difference: The protein has many different monomers (of amino acids) whereas the synthetic polyamide has only two monomers (dicarboxylic acid and diamine).

I did this paper as a mock and my teacher marked it, full marks for this section.
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Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #106 on: June 04, 2010, 06:39:30 pm »
Could someone rexplain please may june 04 q4 b 2 ( i didnt get Ivo's explanation) and b 3 ??


What specifically did you not get, I can try and elaborate.

And for iii) The graph would rise to maximum height, then decrease to zero again.  Why?  Well because aluminium hydroxide (the product formed) dissolves in excess.  Think of the test for aluminium cation:  add aqueous sodium hydroxide, soluble in excess giving a colourless solution.  Same applies here, when a small volume was added, there was precipitate, as you add more and more, it goes colourless, therefore no precipitate.  The common mistake is to think of reactivity.

I hope that clears the issue somewhat.  :D
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Offline 8T

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #107 on: June 04, 2010, 06:45:44 pm »
Oh for b 3 that was perfect mate :D
But b 2 the only thing i get  is that iron 2 is more reactive period. xD
Could u try and elaborate as u said????
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Offline 8T

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #108 on: June 04, 2010, 06:48:43 pm »
Just say:

Similarity: They both have an amide linkage.

Difference: The protein has many different monomers (of amino acids) whereas the synthetic polyamide has only two monomers (dicarboxylic acid and diamine).

I did this paper as a mock and my teacher marked it, full marks for this section.
U seem to make it very easy to understand i already  have + rep u :D
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Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #109 on: June 04, 2010, 06:49:01 pm »
Oh for b 3 that was perfect mate :D
But b 2 the only thing i get  is that iron 2 is more reactive period. xD
Could u try and elaborate as u said????

What, so you don't get why it's Fe(OH)2?
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Offline 8T

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #110 on: June 04, 2010, 06:52:04 pm »
What, so you don't get why it's Fe(OH)2?

no i know that its a formula NOT B1 B2 IVO PLEASE WHY DOES IT HAVE TO REACH 8 I MEAN I REAched 7 but i dnt get whats the reason behind that???
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Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #111 on: June 04, 2010, 06:53:35 pm »
no i know that its a formula NOT B1 B2 IVO PLEASE WHY DOES IT HAVE TO REACH 8 I MEAN I REAched 7 but i dnt get whats the reason behind that???

Just making sure, you're talking about sketching the graph and why the graph reaches 8cm3 maximum height?
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Offline 8T

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #112 on: June 04, 2010, 06:55:07 pm »
Just making sure, you're talking about sketching the graph and why the graph reaches 8cm3 maximum height?
YES, WHY?:)
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Offline Vin

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #113 on: June 04, 2010, 06:57:30 pm »
Elaboration::

1) First reaction, FeCl3 + 3 NaOH ---> 3NaCl  +  Fe(OH)3

so the molar ratio is 1:3 <deduce this ratio by 1)

Second reaction, FeCl2 + 2 NaOH ---> 2NaCl  +  Fe(OH)2

molar ratio 1:2

so 4 cm3 of FeCl2 reacted fully with 8 cm3 of NaOH

Ivo pls. check!

Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #114 on: June 04, 2010, 07:08:28 pm »
YES, WHY?:)

Well, as I explained before.  The sodium hydroxide is in excess, so the maximum needed to fully react with the iron(III) chloride is 12cm3.  So, simplify the ratio down to 12:4 = 3:1/  So 3 moles of sodium hydroxide reacted with 1 mole of iron(III) chloride.  So the balanced equation is:

3NaOH + FeCl3 -> 3NaCl + Fe(OH)3

OK, now if iron (II) chloride:

2NaOH + FeCl2 -> 2NaCl + Fe(OH)2

So 2 moles instead of 3 was required.  So if 3 moles was 12cm3, then 1 mole is 4cm3, then 2 moles must be 8cm3.  Done!  :)
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Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #115 on: June 04, 2010, 07:10:38 pm »
Elaboration::

1) First reaction, FeCl3 + 3 NaOH ---> 3NaCl  +  Fe(OH)3

so the molar ratio is 1:3 <deduce this ratio by 1)

Second reaction, FeCl2 + 2 NaOH ---> 2NaCl  +  Fe(OH)2

molar ratio 1:2

so 4 cm3 of FeCl2 reacted fully with 8 cm3 of NaOH

Ivo pls. check!

Yep, exactly the same!
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Offline 8T

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #116 on: June 04, 2010, 07:24:56 pm »
THANKS A LOT BOTH :D !
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Offline jellybeans

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #117 on: June 05, 2010, 02:12:07 am »
D, obviously.  Because during the day, the plants photosynthesise, so causing oxygen levels to increase.  At night, plants and animals respire so release carbon dioxide, thus reducing the oxygen levels.

OH. i thought the q meant O2 was already high in the morning. lol, :s ;S hhaahaaah thaaankyo

Is this chemistry ::) :P

i was about to answer :P

By the way which paper? I mean which session?

LOLLLLL THANKS and sry  ::) lol /facepalm. totally posted it in the wrong thread  :P :P :P ;D
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« Last Edit: June 05, 2010, 02:16:36 am by jellybeans »
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Offline gaurav95

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #118 on: June 05, 2010, 03:43:20 pm »
some more doubts coming up...............

q4aii),iii)thensame q bii

q6bi its saying ammoniuum ion and ms is giving test abt nitrate ion............

q7b whole

thx in advance........

4) a) ii) Pb(NO3)2 + 2NaCl -> PbCl2 + 2NaNO3
  
        iii) Ag+ + Cl- -> AgCl

    b) ii) Please click here.

6) b) i) Test: Add aqueous sodium hydroxide.  Result: turns damp red litmus paper blue.

7) b) i) Moles of Mg = 3/24 = 0.125
           Moles of CH3COOH = 12/60 = 0.200
           Using ratios given in the equation, to compare, divide 0.2/2 = 0.100 moles of CH3COOH.          
           Therefore, magnesium is in excess.

        ii) The one not in excess: ie. 0.1

        iii) 0.1*24 =2.4dm3

Got it?

Ya got it but q biii u didnt explain

6bi where is this kinda of test mentioned...????

thx a lot..
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Offline Ivo

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Re: IGCSE CHEMISTRY DOUBTS
« Reply #119 on: June 05, 2010, 03:45:15 pm »
Ya got it but q biii u didnt explain

6bi where is this kinda of test mentioned...????

thx a lot..

You mean 6) b) ii) or 7) b) ii)?

And the test for ammonium ions you just need to know.  Memorise them!
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