YES, WHY?
Well, as I explained before. The sodium hydroxide is in excess, so the maximum needed to fully react with the iron(III) chloride is 12cm
3. So, simplify the ratio down to 12:4 = 3:1/ So 3 moles of sodium hydroxide reacted with 1 mole of iron(III) chloride. So the balanced equation is:
3NaOH + FeCl
3 -> 3NaCl + Fe(OH)
3OK, now if iron (II) chloride:
2NaOH + FeCl
2 -> 2NaCl + Fe(OH)
2So 2 moles instead of 3 was required. So if 3 moles was 12cm
3, then 1 mole is 4cm
3, then 2 moles must be 8cm
3. Done!