Author Topic: All Mechanics DOUBTS HERE!!!  (Read 84119 times)

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #660 on: March 05, 2012, 10:31:03 am »
thrid question
resolving for 2kg mass
T-2g=2a
Resolving for 5 kg mass
5g-T=5a
add these
g=5a so a=g/5
sub into T-2g=2a
T=2g+2*g/5 so T=12g/5

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #661 on: March 05, 2012, 10:53:07 am »
q3

Offline LekhB

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Re: All Mechanics DOUBTS HERE!!!
« Reply #662 on: March 10, 2012, 04:50:37 pm »
Thanks a lot.

From a point 120m above ground level, a stone is projected vertically upwards with a speed u m/s. if the stone rises to a height of 5m above the point of projection, calculate(using g= 10 m/s²)
(i)  the value of u,
(ii) the time the stone takes from projection until it reaches the ground level,
(iii) the speed of the stone at ground level.



A particle is projected vertically upwards from ground level. Between 2 seconds and 3 seconds after leaving the ground, it rises 45 m. Calculate (using g=10 m/s²)
(i) the speed of projection
(ii) the maximum height reached
(iii) the time interval for which the particle is above a level of 165m.

Offline LekhB

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Re: All Mechanics DOUBTS HERE!!!
« Reply #663 on: March 10, 2012, 05:09:58 pm »
I hate not getting the same answers as written in my homework book but I don't find anything wrong with my calculations.

A particle is projected vertically upwards from the ground with a speed of 36 m/s. Calculate (using g= 10 m/s²)
(i) the time for which it is above a height of 63m

What I tried :

S: 63m
u: 36 m/s
v: ? m/s
a: 10 m/s²
t: ? s

S= ut + 0.5(at²)

63 = 36(t) + 0.5(10)(t²)

-> 5t² + 36t - 63 = 0

t = [(-36) + (36² - 4(5)(-63)^0.5]/10 or [(-36) - (36² - 4(5)(-63)^0.5]/10

t= 1.46 s.

The answer is t= 1.2s.

And I need t for doing the other parts which are;

(ii) the speed which it has at this height on its way down
(iii) the total time of flight.

Offline LekhB

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Re: All Mechanics DOUBTS HERE!!!
« Reply #664 on: March 10, 2012, 06:03:37 pm »
Two more


From the foot of a vertical cliff 28.8 high, a stone was projected vertically upwards so as just to reach the top. Find its velocity of projection.
One second after the first stone was projected, another stone was allowed to fall from rest from the top of the cliff. The stones passed one another after a further t seconds at a height h m above the ground. Calculate the value of t and h.

Answers : 24 m/s(I got 13.78), 0.7, 26.4

I used to get all of these numbers right in physics. Don't know what happened here...

Another one(in which I got the first answer though):


A particle X is projected vertically upwards from the ground with a velocity of 80 m/s. Calculate the maximum height reached by X. -> I could do this part

The other part: A particle Y is held at a height of 300m above the ground. At the moment when X has droped 80m from its max height, Y is projected downwards with a velocity of v m/s. The particles reach the ground at the same time. Calculate the value of v.

I got v= 103.4

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #665 on: March 10, 2012, 09:35:07 pm »
Except for the last post, here are my answers.
If I used 9.8 for g forgive me

Offline LekhB

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Re: All Mechanics DOUBTS HERE!!!
« Reply #666 on: March 11, 2012, 08:50:31 pm »
Some more ;) This time on connecting particles.





Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #667 on: March 12, 2012, 08:01:44 pm »
those two particle questions from a couple of days ago that I missed out

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #668 on: March 12, 2012, 08:26:51 pm »
the first of those particle on pulley questions

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #669 on: March 12, 2012, 08:50:41 pm »
the second particle on slope question attached

Offline a.k.

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Re: All Mechanics DOUBTS HERE!!!
« Reply #670 on: March 25, 2012, 06:40:09 pm »
i was hopeing someone could help me with this question i have to do for homework, which is from a text book, so i do have the answer, but it is difficult.
Question - Particle A of mass 1kg is at rest 0.2m from the edge of a smooth horizontal 0.8m high table. It is connected by a light inextensible string of length 0.7m to a partcle B of mass 0.5kg. Partcle B is intially at rest at the edge of the table closest to A but then falls off. Assuming B's initial horizontal velocity to be zero find the speed with which A begins to move?

thank you

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #671 on: March 26, 2012, 07:36:04 am »
ak see attachment

Offline fawazomar

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Re: All Mechanics DOUBTS HERE!!!
« Reply #672 on: April 21, 2012, 06:23:25 am »
Hey! I have no idea how the Example 5 Chapter 2 in the M2 Textbook work.
"A light rectangular plate ABCD has AB=20cm and AD=50cm. Particles of mass 2kg, 3kg, 5kg and 5kg are attached to the plate at the points A,B,C,D respectively. Find the distance of the centre of mass of the loaded plane from:
a. AD
b. AB"
Can anyone explain to me how they find the distance??? I know how to find the centre of mass but it stops there.


Offline aaakhtar19

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Re: All Mechanics DOUBTS HERE!!!
« Reply #673 on: May 03, 2012, 07:10:29 am »
assalam.u.alaikum
can any0ne help me solving this questi0n
CIE Board :
paper 04 mechanics
0ctober n0vember 2003
q6

Offline astarmathsandphysics

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Re: All Mechanics DOUBTS HERE!!!
« Reply #674 on: May 06, 2012, 09:37:22 am »
here