Okay, I have solved the first two questions. I'm doing CIE A levels, so I don't have the book for the last question... and I couldn't find that particular page on the Internet. Drat it. Hope you understand my solutions!
First Question:
P is parallel to (
i+4
j), so P= x(
i+4
j)
Q is parallel to (
i+
j), so Q= y(
i+
j)
x & y are to be calulated, as follows:
since R is the resultant of P and Q, R = P+Q
therefore,
R = P+Q
(7
i+16
j) = x(
i+4
j) + y(
i+
j)
(7
i+16
j) = (x
i + 4x
j) + (y
i +y
j)
(7
i+16
j) = [(x+y)
i + (4x+y)
j]
Hence, based on the above equation, you can say that:
x+y = 7
y=7-x >>>>>>>>>>>>>>>>> eqn 1
and,
4x+y = 16
y= 16-4x >>>>>>>>>>>>>>>>>>>eqn 2
Sub eqn 1 into eqn 2:
7-x=16-4x
3x=9
x=3
Sub x=3 into eqn 1
y=7-3
y=4
Therefore, P=x(
i+4
j)
P= 3(
i+4
j)
P=3i + 12jand Q=y(
i+
j)
Q=4(
i+
j)
Q=4i+4jSecond Question:
1 hour passes from 11.00 to 12.00, so the plane moves through a vector of (180i-120j) within this time. The initial vector is (200i+30j).
Therefore, the final vector is:
(200i+30j) + (180i-120j) = (380i-90j)
However, since the question is asking for the distance of the aeroplane from the airport, we must find the magnitude of the above vector via Pythagoras' theorem:
?[380^2+ (-90)^2] =
390.5 km ^For some reason, I couldn't insert the square root sign; it became a '?' instead.