C1 and C2 DOUBTS HERE!!!!!

[elemis]

well i know how to do it by completing the square but what i meant was:
quadratic formula answer : -2+(1/3)(surd21)= -0.472
square completion answer: -2+(surd7/surd3)= -0.472

they want us to express the answer in surd form, so my answer is the quadratic formula one and the one they mentioned in the textbook was the square completion one. Even though they both give the same answer i.e. -0.472, i wanted to know if my answer in surd form is acceptable by the examiners so i wanted to know which paper this q is from??

thanxxx for the help!!! <3

Surd form is acceptable.

[blackberry]

thanxx for helping me out ari and golden girl but itss okayy 
if anyone can just please tell me which paper this is from i'd be glad!!

[The Golden Girl =D]

In January 2008 Q 4 , I can't seem to get the Answer Ends like this :

= surd 245

therefore ; 7surd5  ---->  this is what I can NOT seem to get I got the surd245 but I can't get this one 

Hmm in Q 7 , I don't get how to get X₂₀₀₈ ?! .....

All the Q went well for me Except for Part c) 

Can Someone Please do it for me in DETAIL .

Thank You In an Advance

[Dibss]

In January 2008 Q 4 , I can't seem to get the Answer Ends like this :

= surd 245

therefore ; 7surd5  ---->  this is what I can NOT seem to get I got the surd245 but I can't get this one 

I'll use the word root instead of surd just because I'm used to it.
245 = 49 x 5 right?
so root 245 = root 49 x root 5
= 7 x root 5
Understand?

[Dibss]

Just checked your second question

c) solve 2p^2 + 3p + 1 =1
to get p = 0 (not possible) and p = -3/2
Let me know if I need to elaborate.

d) This one was tricky and I remember being confused by it.
You're meant to substitute your value of p in x2, x3, x4 etc.
Then you'll notice that
x1, x2, x3, x4 = 1, -1/2, 1, -1/2
See the pattern?
So for x2008 (a positve postion) the value will be -1/2

(:

[The Golden Girl =D]

Just checked your second question

c) solve 2p^2 + 3p + 1 =1
to get p = 0 (not possible) and p = -3/2
Let me know if I need to elaborate.

d) This one was tricky and I remember being confused by it.
You're meant to substitute your value of p in x2, x3, x4 etc.
Then you'll notice that
x1, x2, x3, x4 = 1, -1/2, 1, -1/2
See the pattern?
So for x2008 (a positve postion) the value will be -1/2

(:

Thanks I get My Mistake , Thanks Again Sis =]

[Dibss]

You're very welcome. (:

[The Golden Girl =D]

In January 2009 Q8 , Can Someone Please tell me how to draw the reciprocal (y = 2/x ) => I don't know how to , I just drew random lines :S


MS :http://www.scribd.com/doc/15813129/Edexcel-Mathematics-c1-GCE-Core-1-As-Level-January-2009-Mark-scheme-666301

QP: Attached iA =]

[Dibss]

You draw the graph just like you would draw y=1/x but farther from the asymptotes.

So your answer should be like the red line in the figure below:


(:

[The Golden Girl =D]

You draw the graph just like you would draw y=1/x but farther from the asymptotes.

So your answer should be like the red line in the figure below:


(:

Thanks (Jazaki Allaha Kair) =]

[Dibss]

Glad to help. (:

[elemis]

In January 2009 Q8 , Can Someone Please tell me how to draw the reciprocal (y = 2/x ) => I don't know how to , I just drew random lines :S


MS :http://www.scribd.com/doc/15813129/Edexcel-Mathematics-c1-GCE-Core-1-As-Level-January-2009-Mark-scheme-666301

QP: Attached iA =]

This is all in the C1 textbook. There are a few days till the actual exam. What have you been doing ?

[elemis]

On the other hand if you need help. I'm here

[The Golden Girl =D]

Yes . Can you tell me how to do it in the Right Way.

[elemis]

Yes . Can you tell me how to do it in the Right Way.

Yeah, like I said. Check the C1 math textbook.

Whisper/Dibbs has already answered your query on the previous page.