hi guys can some1 post the diagram for oct/nov 09 p4 question 4a
and can sum1 plz explain questions 2a)iv and b)ii (same paper)
thx in advance
n also b) ii)
theres a great method my teacher taught me...
(y) x U = X
(a b) (-1 -4 -4 ) (
-1 -4 -4)
(c d) (1 1 3 ) = ( 2 5 7 )
multiply a b c d in matrix y to matrix U (they are the positions of the image, row 1 is x axis row 2 is y )
(
(-a + b) (-4a+b) (-4a + 7b) )
( (-c+d ) (-4c +d) (-4c+ 7d) )
now solve any two equation my simultaneous method...
so, -a +b = -1 (because the position of this equation is corresponding to matrix "X", look for the colours)
-4a + b = -4
by solving u get a = 1 , b = 0
same for 'c' and 'd' ..u get d= 1 and c = -1
i dont expect u to understand but this method is really good n its really difficult for me to teach online..
read it n try to follow the steps while solving the paper u might get it...