Author Topic: ALL CIE PHYSICS DOUBTS HERE !!!  (Read 172084 times)

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #960 on: February 19, 2012, 12:56:41 pm »
Then they are rounding up extremely.

Offline Most UniQue™

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #961 on: February 19, 2012, 01:10:31 pm »
Then they are rounding up extremely.

Yah Thats what I had been guessing...

Offline emzie

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #962 on: March 02, 2012, 04:41:27 pm »
Hello! Hope you all doing great  :)

I just have this doubt in equilibrium

Is the Kp value affect by change in pressure at constant temperature, if not then why?

Thank in advance!

Offline Most UniQue™

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #963 on: March 02, 2012, 04:49:59 pm »
Hello! Hope you all doing great  :)

I just have this doubt in equilibrium

Is the Kp value affect by change in pressure at constant temperature, if not then why?

Thank in advance!

Isnt this is related to chemistry cuz I have seen it there.

Post it here:

https://studentforums.biz/sciences-149/chemistry-doubts-10366/

Offline emzie

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #964 on: March 02, 2012, 05:27:22 pm »
Oooooops!! My bad  :-X

I was going to post it there, dunno how i can here  :o

Anyway Thanks

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #965 on: March 02, 2012, 08:25:57 pm »
I did that once - ended up in a place I shouldn't be.
When I realised my mistake, I told them, "I've had so much fun. If I ever end up in the wrong place again I will make sure it's this one".

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #966 on: March 03, 2012, 11:19:49 pm »
A jeweler needs to electroplate gold (atomic mass 196.97 u) onto a bracelet. He knows that the charge carriers in the ionic solution are gold ions, and has calculated that he must deposit 0.20 g of gold to reach the necessary thickness. How much current does he need to plate the bracelet in 3.0 hours? (Avogadro's number is 6.02 × 1023.) ??

Mass of 1 mol of gold atoms=197.97*1.67*10^-27*6.02*10^23=198g
no gold atoms needed=0.2/198*6.02*10^23=6.08*10^20
Nogold atoms per sec =6.08*10^20/(3*3600)=5.63*10^16
so current=5.63*10^16*1.6*10^-19=9*10^-3A

Offline ashwinkandel

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #967 on: March 06, 2012, 01:51:26 pm »
I am confused with one question of simple harmonic motion.
« Last Edit: March 06, 2012, 02:13:43 pm by ashwinkandel »

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #968 on: March 06, 2012, 02:56:14 pm »
force due to one spring is F_1 =kx and force due to other is F_2=-kx cos in opposite direction
net forec=F_1-F_2=2kx

Offline Most UniQue™

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #969 on: March 06, 2012, 04:30:41 pm »
force due to one spring is F_1 =kx and force due to other is F_2=-kx cos in opposite direction
net forec=F_1-F_2=2kx

Wow sir your really good in physics!

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #970 on: March 07, 2012, 02:27:22 pm »
Request some videos

Offline ashwinkandel

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #971 on: March 09, 2012, 03:16:55 am »
I would like to request Videos of Quantum Physics. I have attached the topics required for CIE below:

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #972 on: March 09, 2012, 10:25:55 am »
will start making some today

Offline ashwinkandel

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #973 on: March 14, 2012, 04:31:51 pm »
Questions from Nuclear Physics(A2 Part)
I have attached the questions

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #974 on: March 18, 2012, 08:02:23 pm »
a)nuclear processes have a very high activeation energy becasue of the electric repulseion of the protons.
b)helium nuclei have twice the carge of protons so repel even more strongly, making the activation renergy higher
c)mass of reactants=3*4.001506=12.004518u
mass of product=12u
difference=0.004518u
mass=0.004518*1.57*10^-27kg
E=mc^2=0.004518*1.57*10^-27*(3*10^8)^2=6,79*10^-13J