Post by: @d!_†oX!© on October 30, 2009, 07:31:53 am
seriously i haven't seen this anywhere else :o :o
(x:15-2x?7)?(x:5x-2>10-x)
i though maybe ":" sign implies ratio which is actually division
so by taking division(ex, x/(15-2x) i tried to solve it...but this is where i could reach ann dunno how to go about it now :-[ :-[
(x?7)?(5x²-47x+20>0)
PLEASE HELP GUYS!!!!!!
Post by: @d!_†oX!© on October 30, 2009, 07:35:23 am
lke the intersection character and the greater than or equal to character
anyways i'll tell u now:
(x:15-2x>=7)intersection(x:5x-2>10-x)
Post by: Ghost Of Highbury on October 30, 2009, 07:38:52 am
and yea..
(x:15-2x>=7)intersection(x:5x-2>10-x)
is the above the only q?
Post by: Ghost Of Highbury on October 30, 2009, 07:42:51 am
that ":" means "such that"...its dere in the book..read it.
k..so..
solve the inequalitites in both the sides to get
(15-2x>=7) n (5x-2>10-x)
solve them
(x<= 4) n (x>2)
now the left hand side values can be... 4,3,2,1,0 and so on
right hand side.. 3, 4, 5 and so on
the intersection is (3,4)
Post by: ~~~~shreyapril~~~~ on October 30, 2009, 07:43:47 am
and another set is such that x 5x-2>10-x
hope you get it!!
Post by: @d!_†oX!© on October 30, 2009, 07:43:58 am
dts the only question!!!
no link to any other part,....
By the way its from june 1988..
yeah i know its too old...but dude...dts a pretty confusing question!!
Post by: ~~~~shreyapril~~~~ on October 30, 2009, 07:45:33 am
ig uess aadi has solved it!!
not toxic!!
lolzz :D :D
Post by: Ghost Of Highbury on October 30, 2009, 07:45:44 am
solve the inequalitites ..thats it..
and find the intersection..
is the answer (3,4)
Post by: @d!_†oX!© on October 30, 2009, 07:45:53 am
oh yeah i get it now
but i didnt take it as "such as"
because the whole thing was written inside the brackets....so thought maybe its part of the inequality
dude...they gotta make this thing clear in the question!!!
Post by: ~~~~shreyapril~~~~ on October 30, 2009, 07:46:41 am
Post by: sameer210394 on October 30, 2009, 06:41:00 pm
ok guys, here i come with yet another unusual question.... ;D ;D
seriously i haven't seen this anywhere else :o :o
(x:15-2x?7)?(x:5x-2>10-x)
i though maybe ":" sign implies ratio which is actually division
so by taking division(ex, x/(15-2x) i tried to solve it...but this is where i could reach ann dunno how to go about it now :-[ :-[
(x?7)?(5x²-47x+20>0)
PLEASE HELP GUYS!!!!!!
solve both the inequalities separately...
15 - 2x >= 7 5x-2 > 10 - x
15 >= 7 +2x 6x -2 >10
8 >= 2x 6x >12
4 >= x x > 2
now put these inequalities together
4 >= x > 2
this is the answer.
Post by: ~~~~shreyapril~~~~ on October 30, 2009, 06:41:51 pm
it was alread solved!!
how was ur dad's b'day party??
Post by: Ghost Of Highbury on October 31, 2009, 05:44:07 am
solve both the inequalities separately...
15 - 2x >= 7 5x-2 > 10 - x
15 >= 7 +2x 6x -2 >10
8 >= 2x 6x >12
4 >= x x > 2
now put these inequalities together
4 >= x > 2
this is the answer.
the intersection is asked..
so it wud be.. 3,4
By the way..whose b'day party?!?!?
Post by: sameer210394 on October 31, 2009, 06:39:30 am
the intersection is asked..
so it wud be.. 3,4
By the way..whose b'day party?!?!?
ryt, the intersection can be anything between 4 >= x > 2
it can be 3.2 also, it is not mention whether the numbers is a whole numbers ???
i don't i think the answer should be written in this way...
abbey DAd ka B'Day tha...
Post by: Alpha on October 31, 2009, 07:04:00 am
Quote
4 >= x > 2
Simplified, isn't it x > 2 ???
Post by: Ghost Of Highbury on October 31, 2009, 07:09:00 am
Simplified, isn't it x > 2 ???
non..ofcourse not..it is <=4 rite..
Post by: ~~~~shreyapril~~~~ on October 31, 2009, 08:15:38 am
dude try picking up ur phone!!
calling from 1 hr!!
Post by: Alpha on October 31, 2009, 10:33:57 am
non..ofcourse not..it is <=4 rite..
x is greater or equal to 4... See well.
Post by: Ghost Of Highbury on October 31, 2009, 11:02:01 am
x is greater or equal to 4... See well.
u see well...its x is less than or equal to 4
Post by: ~~~~shreyapril~~~~ on October 31, 2009, 11:05:31 am
still that question been discussed!!
read the previous posts clealy!!!
man!!
By the way sorry for being too rude!!!
Post by: Alpha on October 31, 2009, 01:31:37 pm
x is between 2 and 4 or equal to 4... I misplaced the order... 2 < x <= 4
I guess am owing them :P
My excuses.... :)
Post by: ~~~~shreyapril~~~~ on October 31, 2009, 01:33:03 pm
By the way u taken add. math or not??
just to ans my doubts!!
Post by: Alpha on October 31, 2009, 02:02:36 pm
Hey... what doubts?? :P
Post by: ~~~~shreyapril~~~~ on October 31, 2009, 02:03:45 pm
The position vector of C, relative to O, is ki + 25j, where k is a positive constant.
(i) Find the value of k for which the length of BC is 25 units. [3]
(ii) Find the value of k for which ABC is a straight line. [3]
l\just the last part!!!
rest is easy!!!
Post by: nid404 on October 31, 2009, 02:13:52 pm
Post by: Alpha on October 31, 2009, 02:23:55 pm
7 The position vectors of points A and B, relative to an origin O, are 2i + 4j and 6i + 10j respectively.
The position vector of C, relative to O, is ki + 25j, where k is a positive constant.
(i) Find the value of k for which the length of BC is 25 units. [3]
(ii) Find the value of k for which ABC is a straight line. [3]
l\just the last part!!!
rest is easy!!!
If ABC is a str. line,
AB = hBC, where h is a constant.
AB= OB- OA
BC = OC - OB
Continues in the attachment... I allways have problem explaining answers here... Formatting is confusing... Anyway, see the attachment.
Post by: nid404 on October 31, 2009, 02:35:01 pm
Post by: Ghost Of Highbury on October 31, 2009, 03:00:39 pm
7 The position vectors of points A and B, relative to an origin O, are 2i + 4j and 6i + 10j respectively.
The position vector of C, relative to O, is ki + 25j, where k is a positive constant.
(i) Find the value of k for which the length of BC is 25 units. [3]
(ii) Find the value of k for which ABC is a straight line. [3]
l\just the last part!!!
rest is easy!!!
ok..
first. --> AB=OB - OA = 4i + 6j
--> BC = OC - OB = (k-6)i + 15j
BC = x(AB)
(k-6)i + 15j = 4xi + 6xj
k-6 = 4x
6x = 15
x = 2.5
--
k-6 = 4*2.5 = 10
therefore --> k =16
Post by: nid404 on October 31, 2009, 03:05:01 pm
Post by: Ghost Of Highbury on October 31, 2009, 03:10:29 pm
If ABC is a str. line,
AB = hBC, where h is a constant.
AB= OB- OA
BC = OC - OB
Continues in the attachment... I allways have problem explaining answers here... Formatting is confusing... Anyway, see the attachment.
@nid - show how did u use the distance formula?
-----
BC = k-6)i + 15j
therefore
(k-6)2 = 252 - 152 = 400
hence, k = 26
Post by: nid404 on October 31, 2009, 03:13:54 pm
Post by: Ghost Of Highbury on October 31, 2009, 03:15:59 pm
summin like that....can't youarre..show na how u used it..is it the same formula?
Post by: nid404 on October 31, 2009, 03:18:21 pm
arre..show na how u used it..is it the same formula?
yaa..
Post by: Ghost Of Highbury on October 31, 2009, 03:23:34 pm
yaa..kk..i have used that to calculate the length
Post by: ~~~~shreyapril~~~~ on November 01, 2009, 10:55:36 am
aadi is there some simple method to get the answer for that question???
i did not understand ne thing!!!
Post by: Ghost Of Highbury on November 01, 2009, 11:04:46 am
hmmcheck the formula for the magnitude of a vector
aadi is there some simple method to get the answer for that question???
i did not understand ne thing!!!
Post by: ~~~~shreyapril~~~~ on November 01, 2009, 11:06:26 am
By the way i wanted for the 16 wala ans
not for the length!!!
Post by: Ghost Of Highbury on November 01, 2009, 11:19:11 am
now dont say everything..
Post by: ~~~~shreyapril~~~~ on November 01, 2009, 11:20:55 am
got it!!
u explained it on phone!!
done i guess will solve it agian
in same meadtod then i'll undertand
By the way you staying after school irte??
tmr?? for 2 min!!
Post by: Ghost Of Highbury on November 01, 2009, 11:22:31 am
nou guyz have a horrible habit of deviating away from the topic...
got it!!
u explained it on phone!!
done i guess will solve it agian
in same meadtod then i'll undertand
By the way you staying after school irte??
tmr?? for 2 min!!
Post by: @d!_†oX!© on November 01, 2009, 11:23:38 am
haha
EADA's moto
Post by: ~~~~shreyapril~~~~ on November 01, 2009, 11:24:09 am
thanx
By the way om me or ans my question here only!!
if you dont mind!!
By the way wait a sec there is one more question to come check my thread abt ad. math!!
i'll post it there!!
Post by: Alpha on November 01, 2009, 02:27:52 pm
@nid - show how did u use the distance formula?
-----
BC = k-6)i + 15j
therefore
(k-6)2 = 252 - 152 = 400= 20
hence, k = 26
I answered the second part only... He or she just asked for second part...lol
That's the first part! Distance formula is used in 2nd part...
Post by: Alpha on November 01, 2009, 02:38:28 pm
Use the graphical method...
Draw any inclined line on a Cartesian Plane.
I have attached a file to this post. Refer to it.
Let A (x, y) and B(x1, y1).
To find the distance between A and B, i.e, the bold black inclined line, you will need to find the length of the two red dotted lines I have named x and y.
Using Pythagoras' Theorem,
Square of longest side = Sum of squares of the two smallest sides.
Send square to the other side...
>>> Longest side= Sq. root of the sum.
And to find the two smallest sides:
x = 3 - 0 [y1 - y]
y = 3 - 0 [x1 - x]
Note that the triangle formed is a right-angled one.
And now substituting the values for x and y, you will come back to the distance formula given.
Actually, this formula is just another way of using the Pythagoras' Theorem. A diagram would help. But it takes time to draw... Maybe by Tuesday, I'll post the diagram here... It would be easy to understand then.
This formula is used both in Maths and Add Maths.
Good Luck!
Post by: nid404 on November 01, 2009, 02:52:49 pm
so aadi....could u use the distance formula FOR the first one ??
@alpha-i know he asked for the 2nd one ans I know the stuff.....I was asking abt the first part cuz I used the distance formula for the first one and got a different answer
Post by: Ghost Of Highbury on November 01, 2009, 02:54:48 pm
Gradient formula should be used for the second 1....but for the first one i think we need to used distance formula....they did something else.....
so aadi....could u use the distance formula FOR the first one ??
@alpha-i know he asked for the 2nd one ans I know the stuff.....I was asking abt the first part cuz I used the distance formula for the first one and got a different answer
which distance formula?
Post by: nid404 on November 01, 2009, 02:58:02 pm
which distance formula?
arree
root of (x+x1)2+(y+y1)2=AB
Post by: Ghost Of Highbury on November 01, 2009, 03:05:15 pm
arree
root of (x+x1)2+(y+y1)2=AB
its
Post by: nid404 on November 01, 2009, 03:16:54 pm
its
srry yaa yaa.....haste haste :P :P
why can't u use tht??
Post by: Ghost Of Highbury on November 01, 2009, 03:26:07 pm
srry yaa yaa.....haste haste :P :P
why can't u use tht??
i used that re..
first find the vector..and use that formula..bas!
Post by: Alpha on November 01, 2009, 03:30:17 pm
Gradient formula should be used for the second 1....but for the first one i think we need to used distance formula....they did something else.....
so aadi....could u use the distance formula FOR the first one ??
@alpha-i know he asked for the 2nd one ans I know the stuff.....I was asking abt the first part cuz I used the distance formula for the first one and got a different answer
k = 26...
Which answer you got??
There are 2 answers... k = - 14 and k = 26.
-14 is negative; rejected.
Post by: nid404 on November 01, 2009, 03:31:13 pm
Post by: ~~~~shreyapril~~~~ on November 01, 2009, 04:51:33 pm
to spell beans over your hard work i would like to tell you all tat answer is 16!!!
so how to get 16????
Post by: Ghost Of Highbury on November 01, 2009, 04:52:31 pm
hmm...
to spell beans over your hard work i would like to tell you all tat answer is 16!!!
so how to get 16????
didnt i answer it
?
Post by: Ghost Of Highbury on November 01, 2009, 04:53:23 pm
ok..check this
first. --> AB=OB - OA = 4i + 6j
--> BC = OC - OB = (k-6)i + 15j
BC = x(AB)
(k-6)i + 15j = 4xi + 6xj
k-6 = 4x
6x = 15
x = 2.5
--
k-6 = 4*2.5 = 10
therefore --> k =16
Post by: ~~~~shreyapril~~~~ on November 01, 2009, 04:54:23 pm
Post by: nid404 on November 01, 2009, 04:55:11 pm
so what 26 was nodhi and alpha talking abt???
the first part
Post by: Alpha on November 02, 2009, 04:59:24 am
so what 26 was nodhi and alpha talking abt???
The first part! I already answered the second part...
Post by: Alpha on November 02, 2009, 05:04:22 am
If ABC is a str. line,
AB = hBC, where h is a constant.
AB= OB- OA
BC = OC - OB
Continues in the attachment... I allways have problem explaining answers here... Formatting is confusing... Anyway, see the attachment.
Here: Reposted.
Post by: Alpha on November 02, 2009, 05:11:44 am
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 05:13:38 am
i guess alpha is going to top this time!!! :P :P
Post by: nid404 on November 02, 2009, 05:15:09 am
Post by: Alpha on November 02, 2009, 05:17:21 am
@alpha....I know the distance formula. Could you tell me the answer for the first part of the question.....cuz people are gettin different answers. I got 26 usin distance formula....but adi and adi_toxic got 2.5
Okay... Wait... I am.
Post by: Alpha on November 02, 2009, 05:21:11 am
hm..!!
i guess alpha is going to top this time!!! :P :P
Hahahahaaaaa..........bit!!!! :P :P :P :P
Post by: Ghost Of Highbury on November 02, 2009, 05:33:10 am
@alpha....I know the distance formula. Could you tell me the answer for the first part of the question.....cuz people are gettin different answers. I got 26 usin distance formula....but adi and adi_toxic got 2.5what!!?
i didnt get 2.5 dude!!
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 05:33:39 am
not you!!!
Post by: Ghost Of Highbury on November 02, 2009, 05:35:05 am
@nid - show how did u use the distance formula?
-----
BC = k-6)i + 15j
therefore
(k-6)2 = 252 - 152 = 400
hence, k = 26
@shrey - read it again
@nid
check the quoted one!!!
i said 26!!~~
Post by: Alpha on November 02, 2009, 05:38:07 am
Here is your answer... Attached.
Maybe there was a mistake somewhere... in calculations.
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 05:43:33 am
and 16 for second!!!
Post by: Ghost Of Highbury on November 02, 2009, 05:47:29 am
so the final ans if 26 for 1
and 16 for second!!!
was cleared long time ago. check both of my posts.
Post by: nid404 on November 02, 2009, 05:58:57 am
kk....thanks 2 all....
Post by: Alpha on November 02, 2009, 07:16:45 am
Welcome :)
Before you close this forever, just something I wanna add.
x : x - 3, the colon is just a way of expressing mathematical information. It can be read as: x is such that...
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 10:44:36 am
Post by: @d!_†oX!© on November 02, 2009, 12:03:05 pm
@alpha....I know the distance formula. Could you tell me the answer for the first part of the question.....cuz people are gettin different answers. I got 26 usin distance formula....but adi and adi_toxic got 2.5
huh???
i didn't say anything nid!! :-\
lol..i dont even know which question are u talking about!!
@shrey dude she did say aadi and adi_toxic not just me!!
anyways....so is the question solved now???
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 12:04:20 pm
huh???
i didn't say anything nid!! :-\
lol..i dont even know which question are u talking about!!
@shrey dude she did say aadi and adi_toxic not just me!!
anyways....so is the question solved now???
ya pls delete this topic!!
dude i am sorry to post that question!!
everyone is discussing abt it
even if the quesion is solve!!!!
Post by: Ghost Of Highbury on November 02, 2009, 12:05:06 pm
huh???
i didn't say anything nid!! :-\
lol..i dont even know which question are u talking about!!
@shrey dude she did say aadi and adi_toxic not just me!!
anyways....so is the question solved now???
@shrey - itna emoitonal drama kyun kar raha hai? :P
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 12:06:12 pm
tera emotional atyachaar!!!
EADA again!!
EADA rox!!1
Post by: nid404 on November 02, 2009, 12:57:02 pm
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 12:57:52 pm
Post by: nid404 on November 02, 2009, 12:59:06 pm
By the way nids who made this thread??
your the author.....it shows in your post :P :P....I don't have to go back and check :D :D....M not a fooooolll :P
Post by: Ghost Of Highbury on November 02, 2009, 01:00:06 pm
By the way..its adi_toxic and u posted ur add. math doubts here too!
Post by: @d!_†oX!© on November 02, 2009, 01:00:49 pm
i made this thread...but that was for 1 question nd was over then and there..bt this loooooooooooooong convo started!!!
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 01:01:27 pm
if it is aditoxic where is he!???
i want to talk to him!!
i need to tell him to rreomve this thread!!
people are discussing questions even if it is been answered!!
Post by: nid404 on November 02, 2009, 01:06:14 pm
Problem solved naaaaa.....................enough
Post by: Alpha on November 02, 2009, 01:06:49 pm
It's okay... I answered, Adi_Toxic crosschecked. Thanks Adi!
Don't fret now... Let's move on... :)
Shreycool....COOL... Don't worry, Be Happy (Bob Marley) ;D
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 01:07:32 pm
so wdh shud i worry???
Post by: nid404 on November 02, 2009, 01:08:07 pm
Post by: @d!_†oX!© on November 02, 2009, 01:09:08 pm
sab cool hai!!! ;)
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 01:10:48 pm
u know y??
Post by: Alpha on November 02, 2009, 01:11:43 pm
Post by: Alpha on November 02, 2009, 01:12:30 pm
actualy i am cooler than you all...!!
u know y??
We saw. You wrote COOL along with your nick!! Direct from a fridge...lol :D
Post by: nid404 on November 02, 2009, 01:13:27 pm
We saw. You wrote COOL along with your nick!! Direct from a fridge...lol :D
lllloooooolzzz................shrey, m cooler anyday....u don't wanna bet on that man.....when I meet u....ull realize u r wrong :P
Post by: @d!_†oX!© on November 02, 2009, 01:13:50 pm
nice one alpha!!!!! :D :D ;D
Post by: nid404 on November 02, 2009, 01:17:17 pm
naa!!
there is another reason!!
my surname is kul(cool)karni that is kulkarni.... :P :P
lolzz :D
but im still cooler :P...U will know :D
Post by: Alpha on November 02, 2009, 01:17:59 pm
lllloooooolzzz................shrey, m cooler anyday....u don't wanna bet on that man.....when I meet u....ull realize u r wrong :P
Hahaha, if she is COOL, you must be COLD then... :D :D :P
Post by: @d!_†oX!© on November 02, 2009, 01:19:18 pm
I AM THE COOLEST OF U ALL!!!!!!!!!! 8) 8) 8) 8) ;)
HAHAHAHA!!!!!!!!! :D :D :D :D
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 01:20:42 pm
so why are we taking abt physics!!! :P :P :P
lolzz :D :D
Post by: Alpha on November 02, 2009, 01:21:51 pm
By the way, Thanks~~~ LOL
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 01:24:14 pm
nice one alpha!!!
Post by: Alpha on November 02, 2009, 01:24:24 pm
By the way this is a math thread!!
so why are we taking abt physics!!! :P :P :P
lolzz :D :D
Oh! I thought it was meteorology!!! :D :D :D
Thanks for clearing out... ;D
Post by: @d!_†oX!© on November 02, 2009, 01:24:47 pm
AS WELL AS COOL
hahahaha.....no confusion...gr8 combination!!!!!!!
Post by: ~~~~shreyapril~~~~ on November 02, 2009, 01:27:53 pm
Post by: Ghost Of Highbury on November 02, 2009, 02:42:38 pm
but im still cooler :P...U will know :D
wats the reason nid? :P
Post by: nid404 on November 02, 2009, 02:51:43 pm
wats the reason nid? :P
I know I am :D :D.... :P :P