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Author Topic: IGCSE Maths doubt(paper 4)  (Read 14219 times)

Offline @d!_†oX!©

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IGCSE Maths doubt(paper 4)
« on: October 30, 2009, 07:31:53 am »
ok guys, here i come with yet another unusual question.... ;D ;D
seriously i haven't seen this anywhere else :o :o
(x:15-2x?7)?(x:5x-2>10-x)


i though maybe ":" sign implies ratio which is actually division
so by taking division(ex, x/(15-2x) i tried to solve it...but this is where i could reach ann dunno how to go about it now :-[ :-[
(x?7)?(5x²-47x+20>0)

PLEASE HELP GUYS!!!!!!
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Offline @d!_†oX!©

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Re: IGCSE Maths doubt(paper 4)
« Reply #1 on: October 30, 2009, 07:35:23 am »
hey i dunno y but some characters are not coming
lke the intersection character and the greater than or equal to character
anyways i'll tell u now:
(x:15-2x>=7)intersection(x:5x-2>10-x)
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #2 on: October 30, 2009, 07:38:52 am »
which past paper is this?

and yea..

(x:15-2x>=7)intersection(x:5x-2>10-x)

is the above the only q?
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #3 on: October 30, 2009, 07:42:51 am »
ok..heres it..

that ":" means "such that"...its dere in the book..read it.


k..so..
solve the inequalitites in both the sides to get

(15-2x>=7) n (5x-2>10-x)

solve them

(x<= 4) n (x>2)

now the left hand side values can be... 4,3,2,1,0 and so on

right hand side.. 3, 4, 5 and so on

the intersection is (3,4)
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #4 on: October 30, 2009, 07:43:47 am »
dude it means x is a set such that 15-x>7
and another set is such that x 5x-2>10-x

hope you get it!!
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Offline @d!_†oX!©

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Re: IGCSE Maths doubt(paper 4)
« Reply #5 on: October 30, 2009, 07:43:58 am »
yaa!!!!
dts the only question!!!
no link to any other part,....
By the way its from june 1988..
yeah i know its too old...but dude...dts a pretty confusing question!!
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #6 on: October 30, 2009, 07:45:33 am »
done!!
ig uess aadi has solved it!!

not toxic!!

lolzz :D :D
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #7 on: October 30, 2009, 07:45:44 am »
lol..wats the confusing thing

solve the inequalitites ..thats it..

and find the intersection..

is the answer (3,4)
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Offline @d!_†oX!©

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Re: IGCSE Maths doubt(paper 4)
« Reply #8 on: October 30, 2009, 07:45:53 am »
ohhhh!!!!
oh yeah i get it now
but i didnt take it as "such as"
because the whole thing was written inside the brackets....so thought maybe its part of the inequality
dude...they gotta make this thing clear in the question!!!
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #9 on: October 30, 2009, 07:46:41 am »
thaht is what they call IG rite??
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Offline sameer210394

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Re: IGCSE Maths doubt(paper 4)
« Reply #10 on: October 30, 2009, 06:41:00 pm »
Quote from: @d!_†oX!© on October 30, 2009, 07:31:53 am
ok guys, here i come with yet another unusual question.... ;D ;D
seriously i haven't seen this anywhere else :o :o
(x:15-2x?7)?(x:5x-2>10-x)


i though maybe ":" sign implies ratio which is actually division
so by taking division(ex, x/(15-2x) i tried to solve it...but this is where i could reach ann dunno how to go about it now :-[ :-[
(x?7)?(5x²-47x+20>0)

PLEASE HELP GUYS!!!!!!



solve both the inequalities separately...

                     15 - 2x >= 7                              5x-2 > 10 - x
                     15 >= 7 +2x                               6x -2 >10
                     8 >= 2x                                     6x >12
                     4 >= x                                       x > 2

now put these inequalities together

                  4  >=  x   >  2

this is the answer.
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Offline ~~~~shreyapril~~~~

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Re: IGCSE Maths doubt(paper 4)
« Reply #11 on: October 30, 2009, 06:41:51 pm »
done dude!!!

it was alread solved!!
how was ur dad's b'day party??
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Offline Ghost Of Highbury

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Re: IGCSE Maths doubt(paper 4)
« Reply #12 on: October 31, 2009, 05:44:07 am »
Quote from: sameer210394 on October 30, 2009, 06:41:00 pm

solve both the inequalities separately...

                     15 - 2x >= 7                              5x-2 > 10 - x
                     15 >= 7 +2x                               6x -2 >10
                     8 >= 2x                                     6x >12
                     4 >= x                                       x > 2

now put these inequalities together

                  4  >=  x   >  2

this is the answer.


the intersection is asked..

so it wud be.. 3,4

By the way..whose b'day party?!?!?
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Offline sameer210394

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Re: IGCSE Maths doubt(paper 4)
« Reply #13 on: October 31, 2009, 06:39:30 am »
Quote from: A@di on October 31, 2009, 05:44:07 am
the intersection is asked..

so it wud be.. 3,4

By the way..whose b'day party?!?!?

ryt, the intersection can be anything between  4 >= x > 2
it can be 3.2 also,  it is not mention whether the numbers is a whole numbers ???

i don't i think the answer should be written in this way...


abbey DAd ka B'Day tha...
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Re: IGCSE Maths doubt(paper 4)
« Reply #14 on: October 31, 2009, 07:04:00 am »
Quote
4 >= x > 2


Simplified, isn't it x > 2 ???
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