IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: Eamyzz on October 14, 2009, 01:11:10 am
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Personally I solved all da past papers starting 4rm 2000 till 2009
so i kind of gt bored...so i thought about studying in groups ie we will choose da hardest questions n post da years n all of us will start solving dem then we can compare answers n methods this will encouage us to work, study and revise
i hope u lykd ma idea ;) ;)
If any1 has any doubts on any question u can just post it regardless hw easy or hard it is n gd luck 2 all of us :)
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lets start wid
O/N05 - 3
O/ N05 -5
M/J 06-7
O/N06-7
O/N08-7
thats all lets start solving dem n post da answers n check them....plz if any1 has any suggested questions just post them
Good luck ;)
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Shall i stay out of this?
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lets start wid
O/N05 - 3
O/ N05 -5
M/J 06-7
O/N06-7
O/N08-7
thats all lets start solving dem n post da answers n check them....plz if any1 has any suggested questions just post them
Good luck ;)
is this for p1?
ok then.......ono5 q3
(i)in triangle CBE
sin 60=CE/(2sqrt(3)d)
CE=(sqrt3/2)*(2sqrt(3)d)=3d
let X be a point on AD such that BX=ED and BE=XD
sin 30=BX/2d
BX=0.5*2d=d
thus ED=d
so CD=3d+d=4d
part ii will be answered in next post
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ok...part ii
cos 30=AX/2d
AX=2d*(sqrt3/2)=(sqrt3)(d)
cos 60=BE/2sqrt3(d)
BE=2sqrt3*0.5=sqrt3(d)
XD=sqrt3(d)
AD=AX+XD=sqrt3(d)+sqrt3(d)=2sqrt3(d)
tan CAD=CD/AD
tan CAD=4d/2sqrt3d
tan CAD=2/sqrt3
CAD=tan-1(2/sqrt3)
hope this helped
more answers coming soon ;)
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Shall i stay out of this?
of course no ;)
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i gt da same answer slvri
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i gt da same answer slvri
thats good then. so r u appearing in AS math right now?
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thats good then. so r u appearing in AS math right now?
yes wat abt u??
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ppl i was revising n i saw a question its not hard bt it needs thinking its in MJ01 Q11
solve it or have a look at them =)
Good Luck all ;)
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ppl i was revising n i saw a question its not hard bt it needs thinking its in MJ01 Q11
solve it or have a look at them =)
Good Luck all ;)
the may/june papers are not on FEP for a level maths..can u plz upload it here with the markscheme
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the may/june papers are not on FEP for a level maths..can u plz upload it here with the markscheme
Ma scanner isnt working so I will try posting da question gimme 5 minutes :)
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Ma scanner isnt working so I will try posting da question gimme 5 minutes :)
sure..
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Ma scanner isnt working so I will try posting da question gimme 5 minutes :)
The points A and B have position vectors a and b respectively, realative to an origin O. The vectors a and b are given by:
a= 2i-2j+k
b= 6i-2j+3k
i] obtain the value of a.b and hence find angle AOB, correct to the nearest degree.
Vector c has magnitude 12units and is such that c=pa, where p is a constant.
Vector d has magnitude 14 units and is such that d=qb, where q is a constant.
ii] Find the values of p and q
iii] Find the magnitude of d-c
srry i took tym =)
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i am leaving nw because am l8 gd luck n 4 da answers
p=4
q=2
iii] 6
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The points A and B have position vectors a and b respectively, realative to an origin O. The vectors a and b are given by:
a= 2i-2j+k
b= 6i-2j+3k
i] obtain the value of a.b and hence find angle AOB, correct to the nearest degree.
Vector c has magnitude 12units and is such that c=pa, where p is a constant.
Vector d has magnitude 14 units and is such that d=qb, where q is a constant.
ii] Find the values of p and q
iii] Find the magnitude of d-c
i)a.b=2*6+-2*-2+1*3=11
^2+1^2) sqrt(6^2+(-2)^2+3^2)}0.5238)
=58)
p=|c|/|a|=12/3=4 q=|d|/|b|=14/7=2
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The points A and B have position vectors a and b respectively, realative to an origin O. The vectors a and b are given by:
a= 2i-2j+k
b= 6i-2j+3k
i] obtain the value of a.b and hence find angle AOB, correct to the nearest degree.
Vector c has magnitude 12units and is such that c=pa, where p is a constant.
Vector d has magnitude 14 units and is such that d=qb, where q is a constant.
ii] Find the values of p and q
iii] Find the magnitude of d-c
i)a.b=2*6+-2*-2+1*3=11
^2+1^2) sqrt(6^2+(-2)^2+3^2)}0.5238)
=58)
p=|c|/|a|=12/3=4 q=|d|/|b|=14/7=2
Thank you vry much
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do u have any tricky question any tip u wanna give b4 ma exam mr. paul =)
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Get there early. Be at peace. Maybe read an exam paper but probably not answer any questions
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yes wat abt u??
nope not me.......im giving AS and A2 math in june 2010
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Get there early. Be at peace. Maybe read an exam paper but probably not answer any questions
thnk u mr. paul =)
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nope not me.......im giving AS and A2 math in june 2010
gd luck slvri ;) ;)
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hey all hw was da paper?? =)
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i got a question in M1
N 03.....#7 (IV)
i solved almost 3/4 of it....but the final part doesnt wanna get right....so would some1 plz solve IV
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i got a question in M1
N 03.....#7 (IV)
i solved almost 3/4 of it....but the final part doesnt wanna get right....so would some1 plz solve IV
i can use my knowledge of physics and additional mathas to solve this.
first find the (t) where velocity of B is maximum
for this differentiate velocity and equate to 0
d/dx (0.06t - 0.00012t2) = 0.06 - 0.00024t
equate this to 0
0.06 - 0.00024t = 0
0.06 = 0.00024t
t = 0.06/0.00024 = 250s
now
at 250 seconds find the distance covered by B
for finding the distance integrate the velocity formula
<= integration symbol
<(0.06t - 0.00012t2) = 0.03t2 - 0.00004t3 + c
when t = 0 ; s =0 therefore c = 0
so apply t=250 in the formula
s = 0.03t2 - 0.00004t3
s = 1875 - 625 = 1250
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now find the distance traveled by A
u gotta use the diagram for this.
first find the equation of the line AB for this .
u wud get the equation
y = 0.012x + 3.6
substitute x=250 here
y = 6.6
name this point C
find the area of the trapezium ACXY
u wud get the area(distance) as 855
now find the area of the triangle AXO = 240
thus, the total area (distance) = 240 + 855 = 1095
now 1250 - 1095 = 155m
hope that helped
find the diagram attached
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so v is max when a=0
so
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Thanks. I was answering this but always happy when someone beats me tpo it.
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really thank u guys......i did all wt u have done...the problem is about the slope of the equation adi.....my calculator is not getting the acceleration as 0.012
so would u plz show me hw to get that one....maybe i am missing something
nd Thanks again for the really hard work....:)
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OMG>......fool me
i got wt im missing......small mistake
i forgot to subtract the 4.8 from the 7.2 :D LOL hahahahahha
silly mistake for an AL student :D hahaha
Thanks guys!!
really appreciate it.....ur the best!!
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OMG>......fool me
i got wt im missing......small mistake
i forgot to subtract the 4.8 from the 7.2 :D LOL hahahahahha
silly mistake for an AL student :D hahaha
Thanks guys!!
really appreciate it.....ur the best!!
ahh..thats k..happens...and ur welcome.. :)
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GOOD LUCK ALL!...
PAY ATTENTION TO UR SILLY MISTAKES ;D :P
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GOOD LUCK GUYS!!! DO WELL ;D
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can any1 provide me complete list of all formulas for p1??? plzzzz
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it will b attached wid da exam paper :)
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Try this
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Try this
this thing is cool... Thanks
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When I have a full set of notes up there will be summary sheets for each A level maths module