MATH AS QUESTIONS>>>

[Eamyzz]

Personally I solved all da past papers starting 4rm 2000 till 2009
so i kind of gt bored...so i thought about studying in groups ie we will choose da hardest questions n post da years n all of us will start solving dem then we can compare answers n methods this will encouage us to work, study and revise
i hope u lykd ma idea 



If any1 has any doubts on any question u can just post it regardless hw easy or hard it is n gd luck 2 all of us 

[Eamyzz]

lets start wid
O/N05 - 3
O/ N05 -5
M/J 06-7
O/N06-7
O/N08-7

thats all lets start solving dem n post da answers n check them....plz if any1 has any suggested questions just post them
Good luck 

[astarmathsandphysics]

Shall i stay out of this?

[slvri]

lets start wid
O/N05 - 3
O/ N05 -5
M/J 06-7
O/N06-7
O/N08-7

thats all lets start solving dem n post da answers n check them....plz if any1 has any suggested questions just post them
Good luck 

is this for p1?
ok then.......ono5 q3
(i)in triangle CBE
sin 60=CE/(2sqrt(3)d)
CE=(sqrt3/2)*(2sqrt(3)d)=3d
let X be a point on AD such that BX=ED and BE=XD
sin 30=BX/2d
BX=0.5*2d=d
thus ED=d
so CD=3d+d=4d
part ii will be answered in next post

[slvri]

ok...part ii
cos 30=AX/2d
AX=2d*(sqrt3/2)=(sqrt3)(d)
cos 60=BE/2sqrt3(d)
BE=2sqrt3*0.5=sqrt3(d)
XD=sqrt3(d)
AD=AX+XD=sqrt3(d)+sqrt3(d)=2sqrt3(d)
tan CAD=CD/AD
tan CAD=4d/2sqrt3d
tan CAD=2/sqrt3
CAD=tan^-1(2/sqrt3)
hope this helped
more answers coming soon

[Eamyzz]

Shall i stay out of this?

of course no 

[Eamyzz]

i gt da same answer slvri

[slvri]

i gt da same answer slvri

thats good then. so r u appearing in AS math right now?

[Eamyzz]

thats good then. so r u appearing in AS math right now?

yes wat abt u??

[Eamyzz]

ppl i was revising n i saw a question its not hard bt it needs thinking its in MJ01 Q11
solve it or have a look at them =)

Good Luck all

[Ghost Of Highbury]

ppl i was revising n i saw a question its not hard bt it needs thinking its in MJ01 Q11
solve it or have a look at them =)

Good Luck all

the may/june papers are not on FEP for a level maths..can u plz upload it here with the markscheme

[Eamyzz]

the may/june papers are not on FEP for a level maths..can u plz upload it here with the markscheme

Ma scanner isnt working so I will try posting da question gimme 5 minutes 

[Ghost Of Highbury]

Ma scanner isnt working so I will try posting da question gimme 5 minutes 

sure..

[Eamyzz]

Ma scanner isnt working so I will try posting da question gimme 5 minutes 

The points A and  B have position vectors a and b respectively, realative to an origin O. The vectors a and b are given by:
a= 2i-2j+k
b= 6i-2j+3k

i] obtain the value of a.b and hence find angle AOB, correct to the nearest degree.


Vector c has magnitude 12units and is such that c=pa, where p is a constant.
Vector d has magnitude 14 units and is such that d=qb, where q is a constant.

ii] Find the values of p and q
iii] Find the magnitude of d-c


srry i took tym =)

[Eamyzz]

i am leaving nw because am l8 gd luck n 4 da answers
p=4
q=2
iii] 6