IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => University => Topic started by: Tohru Kyo Sohma on August 12, 2012, 06:43:21 pm
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Ok...so i will soon be starting my university and i have to appear for my placement test!
The test is for Business maths and English
I have tried the maths questions from a sample test paper and am finding it difficult as i haven't practiced maths for a year!
Please help me out with my questions!
1. Evaluate (3x^4y^-8/5x^-2y^4z^2)^-2?
2. Find the domain of the function f(x)=2 ?-2+x
Please help me out!
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Give me an hour
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Try this. The second question is not clear. You can post again.
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Thanks astarmathsandphysics
I got how to do the first one
the second one where a question mark appears it is supposed to be a root i copied a symbol but it didn't appear!
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If root x then domain is x>=0
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One factor of 18x^2 -32 is
(a) 9x-32
(b) 9x-16
(c) 3x-2
(d) 3x+4
(e) none of the above
?
which one is it?
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If 2a-b/b=3 then b/a is equal to:
a. 2
b. -0.5
c. 0.5
d. -2
e. none of the above
I think its C
i got this by apply the algebric formula and got a=4 b=2
what do you guys think?
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One mo
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18x^2-32=2(9x^2-16)=2(3x-4)(3x+4)
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(2a-b)/b=2a/3-b/b=2a/b-1=3
2a/b=4 so a/b=2 so b/a=1/2=0.5
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18x^2-32=2(9x^2-16)=2(3x-4)(3x+4)
so it's D?
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(2a-b)/b=2a/3-b/b=2a/b-1=3
2a/b=4 so a/b=2 so b/a=1/2=0.5
so c is right?
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Solve 2x^2+6x-3=0
options:
a. x=(-3+- root of 15)/2
b. x=(-3+- root of 3)/2
c. x=(3+- root of 15)/2
d. x=-3+-root of 15
e. none of the above
I think its E?
Is it right?
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D then C for the first 2.
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D then C for the first 2.
For the third I make it A using the quadratic formula.
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D then C for the first 2.
For the third I make it A using the quadratic formula.
Quadratic formula
x= (-b+- root of b^2-4ac)/2a
x= -6+- root of 36+24 / 2*2
x=-3 +- root of 60 /2
root of 60 is also 2 root of 15
how A then?
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sqrt(60)=sqrt(4*15)=sqrt(4)*sqrt(15)=2 sqrt(15)
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(-6+-sqrt(60))/4 =(-6+-2sqrt(15))/4=(-3+-sqrt(15))/2
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(-6+-sqrt(60))/4 =(-6+-2sqrt(15))/4=(-3+-sqrt(15))/2
wait how did the 2 disappear from there!
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1.Using a phone card to make a long distance phone calls costs a flat fee of $0.85 plus $0.19 per minute starting with the first minute. What id the total cost a phone call which lasts 8 minutes?
a. $2.37
b. $6.00
c. $8.16
d. $1.52
e. none of the above
I THINK ITS A
2. A survey of 250 residence indicated that 170 owned a TV, 130 owned a DVD and 80 owned both TV and DVD. How many donot own a TV or a DVD?
a. 50
b. 90
c. 30
d. 80
e. none of the above
I THINK ITS C[/b]
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The 2 disappeared because I cancelled every term by 2
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0.85+8*0.19=2.37
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I drew a Venn diagram see attachment.
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I drew a Venn diagram see attachment.
0.85+8*0.19=2.37
Thanks
The 2 disappeared because I cancelled every term by 2
can we cancel the same terms from numerator together?
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(3A-4B)^2=
a. 3a^2-4b^2
b. 9a^2-16b^2
c. 9a^2+24ab-16b^2
d. 9a^2+24ab+16b^2
e. none of the above
I think its E
i got my answer as 9A^2-24AB+16B^2
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Solve the equation x(x-12)=-20. the sum of the 2 solution is?
a. 10
b. 12
c. 14
d. 8
e. -8
I think its B
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How many solutions has the system 2x-3y=5 2/3x=y+5/3
a. None
b. exactly one
c. exactly two
d. infinitely many
e. none of the above
I have no idea how to do it?
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Pls help me out
I have my exam within 10 hours
f 9^x-2y =81 then 4y-2x =
a.1
b.3
c.-4
d.4
e. none of the above
I think its C? Am i right?
Q. If f(x)-3x^2 -1 then f(h+1)=
a. 3h^2+6h+4
b. -3h^2+6h-4
c. -3h^2-6h -4
d. -3h^2
e. none of the above
Q. (x^-3 x^2 / x^5)^2/3 equals to
a. x^4
b. 1/x^4
c. 1/x^3
d. x^3
e. none of the above
Q. If p^2=1 and q^2=9. Then the smallest values of p-q is
a. -4
b. 8
c. -10
d. 4
2. None of the above
Q. 5/9x^2 +1/6x =1
a. 10+3x/18x
b. 10+3x /9x
c. 10+3x/18x^2
d. 10+3x/9x^2
e. none of the above
Q. 2/x +3/2x -4/4x=
a. -24/8x^3
b. 24/8x^3
c. 1/7x
e. 9/7x
e. none of the above
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You can canel thoughout by 2 for example (4+6)/4=(2+3)/2
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the first three questions answered in attachment
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more answers
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yet more answers
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You can canel thoughout by 2 for example (4+6)/4=(2+3)/2
I see
the first three questions answered in attachment
Thanks alot for your help
more answers
Thanks again
yet more answers
Thanks yet again
I have 1 last question to ask
what is a domain of a function exactly?
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It is the set of values that can be put into a function
The domain of f(x)=sqrt(x) is x>=0 because you cannot take the square root of a negative number
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good luck
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It is the set of values that can be put into a function
The domain of f(x)=sqrt(x) is x>=0 because you cannot take the square root of a negative number
so the domain of the function f(x)=2 root of -2+x is?
a.x=2
b.x<2
c.x>2
d.x=>2
e.None of the above
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x>=2 actually but some say x>2
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good luck
Thanks
x>=2 actually but some say x>2
i think so too