Author Topic: Maths Help Needed :(  (Read 6372 times)

Offline astarmathsandphysics

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Re: Maths Help Needed :(
« Reply #30 on: August 26, 2012, 08:17:32 pm »
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Offline astarmathsandphysics

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Re: Maths Help Needed :(
« Reply #31 on: August 26, 2012, 08:24:31 pm »
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Offline Tohru Kyo Sohma

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Re: Maths Help Needed :(
« Reply #32 on: August 26, 2012, 08:40:45 pm »
You can canel thoughout by 2 for example (4+6)/4=(2+3)/2
I see
the first three questions answered in attachment
Thanks alot for your help

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Thanks again

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Thanks yet again






I have 1 last question to ask
what is a domain of a function exactly?

Offline astarmathsandphysics

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Re: Maths Help Needed :(
« Reply #33 on: August 26, 2012, 08:42:29 pm »
It is the set of values that can be put into a function
The domain of f(x)=sqrt(x) is x>=0 because you cannot take the square root of a negative number

Offline astarmathsandphysics

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Re: Maths Help Needed :(
« Reply #34 on: August 26, 2012, 08:44:01 pm »
good luck

Offline Tohru Kyo Sohma

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Re: Maths Help Needed :(
« Reply #35 on: August 26, 2012, 08:46:23 pm »
It is the set of values that can be put into a function
The domain of f(x)=sqrt(x) is x>=0 because you cannot take the square root of a negative number
so the domain of the function f(x)=2 root of -2+x is?
a.x=2
b.x<2
c.x>2
d.x=>2
e.None of the above

Offline astarmathsandphysics

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Re: Maths Help Needed :(
« Reply #36 on: August 26, 2012, 08:47:21 pm »
x>=2 actually but some say x>2

Offline Tohru Kyo Sohma

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Re: Maths Help Needed :(
« Reply #37 on: August 26, 2012, 08:48:39 pm »