« previous next »
Pages: [1]   Go Down

Author Topic: Chemistry ppr 4 Help!!!!  (Read 1028 times)

Offline moon

  • SF Citizen
  • ***
  • Posts: 222
  • Reputation: 770
Chemistry ppr 4 Help!!!!
« on: June 06, 2010, 02:36:26 pm »
this question from chemistry ppr4 June. 2005 Q.(1)

plz can anybody help me to draw the ameter in this circuit?

thanx in advance.
Logged

Offline AndrewCedric

  • SF Immigrant
  • **
  • Posts: 88
  • Reputation: 157
Re: Chemistry ppr 4 Help!!!!
« Reply #1 on: June 06, 2010, 03:52:30 pm »
Just draw the ammeter in series with the positive end of the power supply and 1 of the electrodes.
Logged

Offline insane.kid

  • Newbie
  • *
  • Posts: 20
  • Reputation: 17
Re: Chemistry ppr 4 Help!!!!
« Reply #2 on: June 06, 2010, 05:39:04 pm »
Guys I have one question frm A level chem PAPER 4 S06 4d)iv) why do the Bromine have to be at 2,6 to OH y not 2,6 TO alkyl chain attached? hopefully you guys understood and plz reply soon :) thank you
Logged

Offline CHEMMASTER6000

  • SF Immigrant
  • **
  • Posts: 70
  • Reputation: 755
Re: Chemistry ppr 4 Help!!!!
« Reply #3 on: June 06, 2010, 05:46:23 pm »
we dont know why but , we learn it as a rule. OH is considered activating group which makes it combine to br as such .  cl are deactivating groups which makes it combine to 2 and 5 .
Logged

Offline insane.kid

  • Newbie
  • *
  • Posts: 20
  • Reputation: 17
Re: Chemistry ppr 4 Help!!!!
« Reply #4 on: June 06, 2010, 05:51:46 pm »
but y doesnt it go 2,6 to alkyl group y the OH and are u sure tht cl goes 2,5 :S i never knew tht
Logged

Offline moon

  • SF Citizen
  • ***
  • Posts: 222
  • Reputation: 770
Re: Chemistry ppr 4 Help!!!!
« Reply #5 on: June 06, 2010, 06:23:41 pm »
can u plz check this answer?
Logged

Offline CHEMMASTER6000

  • SF Immigrant
  • **
  • Posts: 70
  • Reputation: 755
Re: Chemistry ppr 4 Help!!!!
« Reply #6 on: June 07, 2010, 03:12:21 am »
dude i looked at the paper, its an amino acid , nothing hppens to the amino acid. the only active groupas are the amide and the carboxylic acid on the sides and of course the r group. The R group is the benzene ring which is the reactive point  ;D
Logged
Pages: [1]   Go Up
« previous next »