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Chemistry ppr 4 Help!!!!
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Topic: Chemistry ppr 4 Help!!!! (Read 1027 times)
moon
SF Citizen
Posts: 222
Reputation: 770
Chemistry ppr 4 Help!!!!
«
on:
June 06, 2010, 02:36:26 pm »
this question from chemistry ppr4 June. 2005 Q.(1)
plz can anybody help me to draw the ameter in this circuit?
thanx in advance.
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AndrewCedric
SF Immigrant
Posts: 88
Reputation: 157
Re: Chemistry ppr 4 Help!!!!
«
Reply #1 on:
June 06, 2010, 03:52:30 pm »
Just draw the ammeter in series with the positive end of the power supply and 1 of the electrodes.
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insane.kid
Newbie
Posts: 20
Reputation: 17
Re: Chemistry ppr 4 Help!!!!
«
Reply #2 on:
June 06, 2010, 05:39:04 pm »
Guys I have one question frm A level chem PAPER 4 S06 4d)iv) why do the Bromine have to be at 2,6 to OH y not 2,6 TO alkyl chain attached? hopefully you guys understood and plz reply soon
thank you
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CHEMMASTER6000
SF Immigrant
Posts: 70
Reputation: 755
Re: Chemistry ppr 4 Help!!!!
«
Reply #3 on:
June 06, 2010, 05:46:23 pm »
we dont know why but , we learn it as a rule. OH is considered activating group which makes it combine to br as such . cl are deactivating groups which makes it combine to 2 and 5 .
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insane.kid
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Posts: 20
Reputation: 17
Re: Chemistry ppr 4 Help!!!!
«
Reply #4 on:
June 06, 2010, 05:51:46 pm »
but y doesnt it go 2,6 to alkyl group y the OH and are u sure tht cl goes 2,5 :S i never knew tht
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moon
SF Citizen
Posts: 222
Reputation: 770
Re: Chemistry ppr 4 Help!!!!
«
Reply #5 on:
June 06, 2010, 06:23:41 pm »
can u plz check this answer?
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CHEMMASTER6000
SF Immigrant
Posts: 70
Reputation: 755
Re: Chemistry ppr 4 Help!!!!
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Reply #6 on:
June 07, 2010, 03:12:21 am »
dude i looked at the paper, its an amino acid , nothing hppens to the amino acid. the only active groupas are the amide and the carboxylic acid on the sides and of course the r group. The R group is the benzene ring which is the reactive point
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Chemistry ppr 4 Help!!!!